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Math peeps explain this to me

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its equal to 0 or -1, depending when you stop the ...

Which is my point. The OP depends on 1-1+1-1... being equal to 0.5, which depends on using an alternate definition called a Cesaro summation. The Cesaro sum 1+0-1... is 2/3.

So the sum of 1-1+1-1... is not 0.5. It is undefined for the traditional definition of summation. That's what bothers me about the video.
 
"We don't know so we take the average"

I'm sure they are right, far smarter than I am, but that just feels like "Eh, math, close enough". LOL

I'm with you.

But I also kinda get it. They are talking infinity, so there really isn't an end, or a specific point in the string where it is defined. I think quantum physics, and I think atoms that are here and there at the same time.

If the state of the problem is either 1 or zero, depending on when you say "Stop," it never really is 1 or zero, because you saying "stop" is actually arbitrary--not the fact that you decide to define the sum as 1/2. It is 1/2, because it can only be 1/2, as it is most closely approximated as the ave value of it's 2 constant states.

er, something like that. I dunno. I hate math.
 
Which is my point. The OP depends on 1-1+1-1... being equal to 0.5, which depends on using an alternate definition called a Cesaro summation. The Cesaro sum 1+0-1... is 2/3.

So the sum of 1-1+1-1... is not 0.5. It is undefined for the traditional definition of summation. That's what bothers me about the video.

Can you explain how 1+0-1... is 2/3 and how 1-1+1.. is undefined?
 
Can you explain how 1+0-1... is 2/3 and how 1-1+1.. is undefined?

He's saying that 1-1+1-1+... is not really 0.5. But, for the people who think that it's 0.5, then by their exact same mathematics, 1+0-1+1+0-1+... = 2/3.

If you look at partial sums,
sum of 1 term (S_1) = 1
S_2 = 1
S_3 = 0.
S_4 = 1
S_5 = 1
S_6 = 0.

2/3 of the time, it's 1, 1/3 of the time, it's 0. So, a weighted average... the sum is 2/3. (nonsense.)
 
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