You have a plane and a conveyor belt.

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InlineFour

Banned
Nov 1, 2005
3,194
0
0
Originally posted by: Kenazo
I recant my position... Given the original post's stipulations, it won't take off unless the thrust of the engine is greater than the mass of the airplane. otherwise it's going to stay there.

The OP:
The plane increases it's thrust and the wheels begin to rotate. The belt compensates for the rotation of the wheels in reverse, as in the belt moves in reverse exactly as fast as the wheels move forward.

The constraints set out by the scenario tell me it's not going to happen, unless the engine has more thrust than weight. Of course in real life there's no way this is going to happen.

that's what i keep thinking. the belt will always move in the same exact speed as the wheels.

i think we can simplify the question and say that, a plane is moving at 10mph and the conveyor belt is moving in reverse at 10mph, will the plane take off?
 
Feb 19, 2001
20,155
23
81
Can someone answer this in terms of conservation of momentum though.

If you have a rocket engine on a plane and the same situation. You're expelling gas out backwards.... but where is the forward motion.
 

JMWarren

Golden Member
Nov 6, 2003
1,201
0
0
Maybe it will help people to think of it this way.

A plane that has just touched down has a wheel speed = air speed. If its on a belt and the belt begins to move.

Assume at touch down belt = 0, plane = 75kts.

If the belt beings to move at 5 kts in the same direction the plane is moving the plane will not increase in speed but the wheels will spin faster. Since the wheels are on bearings there is nothing to transfer their rotation to the planes motion.

Now assume you land on a belt moving at 75kts doing 75kts in the plane, with the breaks locked up. If the belt increases speed so will the plane (assuming the tires maintain traction).

If the belt continues to increase in speed and you release the breaks the plane will begin to lose airspeed (due to drag). As this occurs the tires will begin to spin isolating the plane from the ground.

Apply this to take off and the tires/bearings ISOLATE the plane from the motion of the belt. The plane will move forward and takeoff in the same distance it usually does.
 

mercanucaribe

Banned
Oct 20, 2004
9,763
1
0
THE PLANE DOES MOVE FORWARD ON THE CONVEYOR BELT. IT DOES NOT STAY STILL. A THREADMILL ACTING ON FREE SPINNING WHEELS CAN NOT COUNTERACT THE THRUST OF THE ENGINES AND THE WHEELS WILL ONLY SPIN FASTER AND FASTER.
 

Number1

Diamond Member
Feb 24, 2006
7,881
549
126
Originally posted by: deathkoba
Originally posted by: Number1
Originally posted by: alien42
Originally posted by: Number1
Plane stopped = wheel speed 0 = treadmill speed 0

Plane MOVING at 5 MPH = treadmill 5 MPH backward = wheel speed 10MPH.

Notice the emphasis on the word MOVING. The plane IS moving forward; therefore it is generating air flow around the wing. Once it is moving fast enough it will take off.

5mph one way negated by 5mph the other way means the plane is not moving

Where did the speed go? The only way to have the treadmill moving is to have the plane move forward.

If you mean by the plane's wheels are rotating at 5MPH and the treadmill moving at 5MPH, then the actual location of the plane does not change, and unless there is wind blowing into the front of the aircraft, the plane is actually performing at 0 airspeed.

Airspeed is what determines the plane's flight performance and not the perception of the viewer from the ground. If the conveyor belt keeps going and the pilot cuts the engines, the plane will start moving backwards gradually and keep speeding up (backwards that is) until it matches the belt speed. Crank the engines again and it will reduce the backwards motion until it reaches par (meaning it looks still from afar.) When it reaches par and even more power is applied to the engine, the plane will visually move foward. Only then will there be any level of headwind. To take off, it's just a matter of the aircraft reaching the required takeoff headwind/airspeed, not how fast the wheels are spinning.

Headwind = what's shown on the airspeed indicator. Airspeed = direct relation to the performance of the aircraft.

The treadmill matches the speed of the plane's wheel. The wheels are not driven so the only way they would turn would be as a result of the plane moving forward.
 

JMWarren

Golden Member
Nov 6, 2003
1,201
0
0
Originally posted by: DLeRium
Can someone answer this in terms of conservation of momentum though.

If you have a rocket engine on a plane and the same situation. You're expelling gas out backwards.... but where is the forward motion.

Assume there is no friction in the wheel bearings. Start to move the belt without moving the plane. The plane will stay in the same place as the wheels begin to spin. Now apply power to the planes engins. The plane will move forward as the wheels spin backwards.
 

PurdueRy

Lifer
Nov 12, 2004
13,837
4
0
Originally posted by: DLeRium
Originally posted by: PurdueRy
Originally posted by: InlineFour
purduery, you're saying that the plane will take off?

yes

So this is why I think my Purdue Engineering friend is incompetent. This is why we Cal students get the job.

Your assumption of 5MPH assumes that the wheels are spinning FASTER than the treadmill..... This is like walking at the same speed the treadmill is going. The treadmill is not at a fixed speed. It goes in reverse as fast as the wheel does.

Thus dv/dt = 0. Without any net motion there is no airflow, thus no takeoff.

http://www.straightdope.com/columns/060203.html

http://www.straightdope.com/columns/060303.html


Find something better to do than insulting someone's education
 

JMWarren

Golden Member
Nov 6, 2003
1,201
0
0
Originally posted by: InlineFour
Originally posted by: Kenazo
I recant my position... Given the original post's stipulations, it won't take off unless the thrust of the engine is greater than the mass of the airplane. otherwise it's going to stay there.

The OP:
The plane increases it's thrust and the wheels begin to rotate. The belt compensates for the rotation of the wheels in reverse, as in the belt moves in reverse exactly as fast as the wheels move forward.

The constraints set out by the scenario tell me it's not going to happen, unless the engine has more thrust than weight. Of course in real life there's no way this is going to happen.

that's what i keep thinking. the belt will always move in the same exact speed as the wheels.

i think we can simplify the question and say that, a plane is moving at 10mph and the conveyor belt is moving in reverse at 10mph, will the plane take off?


If the plane can fly at 10mph it will take off.

The treadmill moving backwords doesn't matter. The wheels isolate the body of the plane from the treadmill. The wheels will be rotating BACKWARDS at 20mph.
 

Eli

Super Moderator | Elite Member
Oct 9, 1999
50,419
8
81
No, airplanes require the flow of air over the wings to create lift.

Edit: SHould've read the thread first. Interesting.
 
Feb 19, 2001
20,155
23
81
Originally posted by: Number1
Originally posted by: deathkoba
Originally posted by: Number1
Originally posted by: alien42
Originally posted by: Number1
Plane stopped = wheel speed 0 = treadmill speed 0

Plane MOVING at 5 MPH = treadmill 5 MPH backward = wheel speed 10MPH.

Notice the emphasis on the word MOVING. The plane IS moving forward; therefore it is generating air flow around the wing. Once it is moving fast enough it will take off.

5mph one way negated by 5mph the other way means the plane is not moving

Where did the speed go? The only way to have the treadmill moving is to have the plane move forward.

If you mean by the plane's wheels are rotating at 5MPH and the treadmill moving at 5MPH, then the actual location of the plane does not change, and unless there is wind blowing into the front of the aircraft, the plane is actually performing at 0 airspeed.

Airspeed is what determines the plane's flight performance and not the perception of the viewer from the ground. If the conveyor belt keeps going and the pilot cuts the engines, the plane will start moving backwards gradually and keep speeding up (backwards that is) until it matches the belt speed. Crank the engines again and it will reduce the backwards motion until it reaches par (meaning it looks still from afar.) When it reaches par and even more power is applied to the engine, the plane will visually move foward. Only then will there be any level of headwind. To take off, it's just a matter of the aircraft reaching the required takeoff headwind/airspeed, not how fast the wheels are spinning.

Headwind = what's shown on the airspeed indicator. Airspeed = direct relation to the performance of the aircraft.

The treadmill matches the speed of the plane's wheel. The wheels are not driven so the only way they would turn would be as a result of the plane moving forward.

The plane moves forward with RESPECT TO THE TREADMILL. If your reference frame "S" is in the treadmill being your ground, you will be moving. In this case, an object in reference frame S that is not moving (i.e. the treadmill is going backwards and the plane is glued to the treadmill), the object experiences airflow in the REVERSE direction. Now we know that S is moving backwards and the object is moving forward. Airflow is 0.

Try reference frame S' on the ground. The plane is not moving with respect to an observer on the ground, but the plane is moving with respect to the treadmill. However, AIR is not moving with respect to S', and nor is the plane. Thus air is not moving with respect to reference frame S'' (the plane). Thus there is no freaking airflow over the wings and thus there is no takeoff.

Relativity my friend. QED



Originally posted by: JMWarren
Originally posted by: InlineFour
Originally posted by: Kenazo
I recant my position... Given the original post's stipulations, it won't take off unless the thrust of the engine is greater than the mass of the airplane. otherwise it's going to stay there.

The OP:
The plane increases it's thrust and the wheels begin to rotate. The belt compensates for the rotation of the wheels in reverse, as in the belt moves in reverse exactly as fast as the wheels move forward.

The constraints set out by the scenario tell me it's not going to happen, unless the engine has more thrust than weight. Of course in real life there's no way this is going to happen.

that's what i keep thinking. the belt will always move in the same exact speed as the wheels.

i think we can simplify the question and say that, a plane is moving at 10mph and the conveyor belt is moving in reverse at 10mph, will the plane take off?


If the plane can fly at 10mph it will take off.

The treadmill moving backwords doesn't matter. The wheels isolate the body of the plane from the treadmill. The wheels will be rotating BACKWARDS at 20mph.

I don't know where you graduated from but if you read the problem, the treadmill moves as fast as the wheels do. There is no motion. You cant even throw out ANY numbers at all.
 

Armitage

Banned
Feb 23, 2001
8,086
0
0
Originally posted by: Kenazo
I recant my position... Given the original post's stipulations, it won't take off unless the thrust of the engine is greater than the mass of the airplane. otherwise it's going to stay there.

The OP:
The plane increases it's thrust and the wheels begin to rotate. The belt compensates for the rotation of the wheels in reverse, as in the belt moves in reverse exactly as fast as the wheels move forward.

The constraints set out by the scenario tell me it's not going to happen, unless the engine has more thrust than weight. Of course in real life there's no way this is going to happen.


LMAO - in other news the BBC reports a loud humming noise from Westminster Abbey. Speculation is that it is Newton spinning in his grave.
 

JMWarren

Golden Member
Nov 6, 2003
1,201
0
0
If the plane is tied down and you start to move the belt the wheels will spin. If there is 0 friction in the bearings you can release the tie downs and the wheels will still spin and the plane will remain stationary. If you apply power the plane will begin to move forwards as the wheels continue to counter act the force of the belt even if the belt increases in speed. The belt could be moving at 500mph and the plane in the oposite directionat 100mph. THE BELT SPEED IS IRREVELANT TO THE PLANE SPEED AS THE WHEELS ISOLATE THE PLANE FROM THE BELT!
 

TankGuys

Golden Member
Jun 3, 2005
1,080
0
0
The bottom line here is that it depends on the wording of the question, and how people interpret it. There are some "wordings" where the plane won't take off, and some that the plane will take off.

If people make the strict assuption that the treadmill moves backwards at the same speed as the wheels rotate forward, you run into issues of infinite acceleration and other fun stuff, and the plane won't take off.

If people assume the belt moves backward at a velocity equal to and opposite the plane's speed, then the plane takes off just fine, wheels spinning 2x the normal speed.



Consider this thought experiment:

You know those toy cars that you roll backwards, and when you let go, they move forward? Let's say you put it on a STILL treadmill. The car moves forward fine right? Now, put said car on treadmill that's moving backwards, and we all know the car moves at it's speed minus the speed of the treadmill, right? This is because the propulsion system of the car depends on the spinning of its wheels, which are affected by the treadmill. This all makes sense so far, yes?

Now, consider a standard matchbox car. Put that car on a non-moving treadmill. What happens? It stays still. Now, turn the treadmill on, and what happens? Car rolls backwards, right? Now, reach out your hand and hold the car still, while the readmill is moving. What happens now? The car stays put right? Do you think it takes much force to actually hold it still? (try it!) NOW... try pushing the car forward, while the treadmill is moving. You can do it, right? Is it hard? Is it noticably harder than pushing the car forward when the treadmill is not moving? (again, try it!)

This is exactly what happens with a plane. The force of the engines is pushing on the plane - NOT the treadmill. Aside from the bit of friction at the axle that the engine thrust has to overcome, the engines, air, and plane don't really care what happens to the treadmill.

Seriously, anyone who has a treadmill and a matchbox car at home can easily prove this to themselves :)
 

JMWarren

Golden Member
Nov 6, 2003
1,201
0
0
Originally posted by: DLeRium
Originally posted by: Number1
Originally posted by: deathkoba
Originally posted by: Number1
Originally posted by: alien42
Originally posted by: Number1
Plane stopped = wheel speed 0 = treadmill speed 0

Plane MOVING at 5 MPH = treadmill 5 MPH backward = wheel speed 10MPH.

Notice the emphasis on the word MOVING. The plane IS moving forward; therefore it is generating air flow around the wing. Once it is moving fast enough it will take off.

5mph one way negated by 5mph the other way means the plane is not moving

Where did the speed go? The only way to have the treadmill moving is to have the plane move forward.

If you mean by the plane's wheels are rotating at 5MPH and the treadmill moving at 5MPH, then the actual location of the plane does not change, and unless there is wind blowing into the front of the aircraft, the plane is actually performing at 0 airspeed.

Airspeed is what determines the plane's flight performance and not the perception of the viewer from the ground. If the conveyor belt keeps going and the pilot cuts the engines, the plane will start moving backwards gradually and keep speeding up (backwards that is) until it matches the belt speed. Crank the engines again and it will reduce the backwards motion until it reaches par (meaning it looks still from afar.) When it reaches par and even more power is applied to the engine, the plane will visually move foward. Only then will there be any level of headwind. To take off, it's just a matter of the aircraft reaching the required takeoff headwind/airspeed, not how fast the wheels are spinning.

Headwind = what's shown on the airspeed indicator. Airspeed = direct relation to the performance of the aircraft.

The treadmill matches the speed of the plane's wheel. The wheels are not driven so the only way they would turn would be as a result of the plane moving forward.

The plane moves forward with RESPECT TO THE TREADMILL. If your reference frame "S" is in the treadmill being your ground, you will be moving. In this case, an object in reference frame S that is not moving (i.e. the treadmill is going backwards and the plane is glued to the treadmill), the object experiences airflow in the REVERSE direction. Now we know that S is moving backwards and the object is moving forward. Airflow is 0.

Try reference frame S' on the ground. The plane is not moving with respect to an observer on the ground, but the plane is moving with respect to the treadmill. However, AIR is not moving with respect to S', and nor is the plane. Thus air is not moving with respect to reference frame S'' (the plane). Thus there is no freaking airflow over the wings and thus there is no takeoff.

Relativity my friend. QED



Originally posted by: JMWarren
Originally posted by: InlineFour
Originally posted by: Kenazo
I recant my position... Given the original post's stipulations, it won't take off unless the thrust of the engine is greater than the mass of the airplane. otherwise it's going to stay there.

The OP:
The plane increases it's thrust and the wheels begin to rotate. The belt compensates for the rotation of the wheels in reverse, as in the belt moves in reverse exactly as fast as the wheels move forward.

The constraints set out by the scenario tell me it's not going to happen, unless the engine has more thrust than weight. Of course in real life there's no way this is going to happen.

that's what i keep thinking. the belt will always move in the same exact speed as the wheels.

i think we can simplify the question and say that, a plane is moving at 10mph and the conveyor belt is moving in reverse at 10mph, will the plane take off?


If the plane can fly at 10mph it will take off.

The treadmill moving backwords doesn't matter. The wheels isolate the body of the plane from the treadmill. The wheels will be rotating BACKWARDS at 20mph.

I don't know where you graduated from but if you read the problem, the treadmill moves as fast as the wheels do. There is no motion. You cant even throw out ANY numbers at all.


The wheels DO NOT TRANSFER MOTION!

Leave the plane at idle and move the treadmill. Since there is 0 friction in the bearings the plane will not move and the wheels will begin to spin backwards. The speed of the belt doesn't matter.
 

alien42

Lifer
Nov 28, 2004
12,869
3,299
136
Originally posted by: TankGuys
The bottom line here is that it depends on the wording of the question, and how people interpret it. There are some "wordings" where the plane won't take off, and some that the plane will take off.

If people make the strict assuption that the treadmill moves backwards at the same speed as the wheels rotate forward, you run into issues of infinite acceleration and other fun stuff, and the plane won't take off.

If people assume the belt moves backward at a velocity equal to and opposite the plane's speed, then the plane takes off just fine, wheels spinning 2x the normal speed.



Consider this thought experiment:

You know those toy cars that you roll backwards, and when you let go, they move forward? Let's say you put it on a STILL treadmill. The car moves forward fine right? Now, put said car on treadmill that's moving backwards, and we all know the car moves at it's speed minus the speed of the treadmill, right? This is because the propulsion system of the car depends on the spinning of its wheels, which are affected by the treadmill. This all makes sense so far, yes?

Now, consider a standard matchbox car. Put that car on a non-moving treadmill. What happens? It stays still. Now, turn the treadmill on, and what happens? Car rolls backwards, right? Now, reach out your hand and hold the car still, while the readmill is moving. What happens now? The car stays put right? Do you think it takes much force to actually hold it still? (try it!) NOW... try pushing the car forward, while the treadmill is moving. You can do it, right? Is it hard? Is it noticably harder than pushing the car forward when the treadmill is not moving? (again, try it!)

This is exactly what happens with a plane. The force of the engines is pushing on the plane - NOT the treadmill. Aside from the bit of friction at the axle that the engine thrust has to overcome, the engines, air, and plane don't really care what happens to the treadmill.

Seriously, anyone who has a treadmill and a matchbox car at home can easily prove this to themselves :)

this is the only completely accurate post
 

JMWarren

Golden Member
Nov 6, 2003
1,201
0
0
Originally posted by: TankGuys
The bottom line here is that it depends on the wording of the question, and how people interpret it. There are some "wordings" where the plane won't take off, and some that the plane will take off.

If people make the strict assuption that the treadmill moves backwards at the same speed as the wheels rotate forward, you run into issues of infinite acceleration and other fun stuff, and the plane won't take off.

If people assume the belt moves backward at a velocity equal to and opposite the plane's speed, then the plane takes off just fine, wheels spinning 2x the normal speed.



Consider this thought experiment:

You know those toy cars that you roll backwards, and when you let go, they move forward? Let's say you put it on a STILL treadmill. The car moves forward fine right? Now, put said car on treadmill that's moving backwards, and we all know the car moves at it's speed minus the speed of the treadmill, right? This is because the propulsion system of the car depends on the spinning of its wheels, which are affected by the treadmill. This all makes sense so far, yes?

Now, consider a standard matchbox car. Put that car on a non-moving treadmill. What happens? It stays still. Now, turn the treadmill on, and what happens? Car rolls backwards, right? Now, reach out your hand and hold the car still, while the readmill is moving. What happens now? The car stays put right? Do you think it takes much force to actually hold it still? (try it!) NOW... try pushing the car forward, while the treadmill is moving. You can do it, right? Is it hard? Is it noticably harder than pushing the car forward when the treadmill is not moving? (again, try it!)

This is exactly what happens with a plane. The force of the engines is pushing on the plane - NOT the treadmill. Aside from the bit of friction at the axle that the engine thrust has to overcome, the engines, air, and plane don't really care what happens to the treadmill.

Seriously, anyone who has a treadmill and a matchbox car at home can easily prove this to themselves :)


QFT /Thread
 

PurdueRy

Lifer
Nov 12, 2004
13,837
4
0
Originally posted by: TankGuys
The bottom line here is that it depends on the wording of the question, and how people interpret it. There are some "wordings" where the plane won't take off, and some that the plane will take off.

If people make the strict assuption that the treadmill moves backwards at the same speed as the wheels rotate forward, you run into issues of infinite acceleration and other fun stuff, and the plane won't take off.

If people assume the belt moves backward at a velocity equal to and opposite the plane's speed, then the plane takes off just fine, wheels spinning 2x the normal speed.



Consider this thought experiment:

You know those toy cars that you roll backwards, and when you let go, they move forward? Let's say you put it on a STILL treadmill. The car moves forward fine right? Now, put said car on treadmill that's moving backwards, and we all know the car moves at it's speed minus the speed of the treadmill, right? This is because the propulsion system of the car depends on the spinning of its wheels, which are affected by the treadmill. This all makes sense so far, yes?

Now, consider a standard matchbox car. Put that car on a non-moving treadmill. What happens? It stays still. Now, turn the treadmill on, and what happens? Car rolls backwards, right? Now, reach out your hand and hold the car still, while the readmill is moving. What happens now? The car stays put right? Do you think it takes much force to actually hold it still? (try it!) NOW... try pushing the car forward, while the treadmill is moving. You can do it, right? Is it hard? Is it noticably harder than pushing the car forward when the treadmill is not moving? (again, try it!)

This is exactly what happens with a plane. The force of the engines is pushing on the plane - NOT the treadmill. Aside from the bit of friction at the axle that the engine thrust has to overcome, the engines, air, and plane don't really care what happens to the treadmill.

Seriously, anyone who has a treadmill and a matchbox car at home can easily prove this to themselves :)

excellent example.

Think of a treadmill going downhill. The force cause by gravity simulates the engines force. The treadmill can rotate all it wan't backward but that won't do anything to stop the acceleration of a toy car.(wheels are not tied to power on toy car)
 

Number1

Diamond Member
Feb 24, 2006
7,881
549
126
Originally posted by: DLeRium
Originally posted by: Number1
Originally posted by: deathkoba
Originally posted by: Number1
Originally posted by: alien42
Originally posted by: Number1
Plane stopped = wheel speed 0 = treadmill speed 0

Plane MOVING at 5 MPH = treadmill 5 MPH backward = wheel speed 10MPH.

Notice the emphasis on the word MOVING. The plane IS moving forward; therefore it is generating air flow around the wing. Once it is moving fast enough it will take off.

5mph one way negated by 5mph the other way means the plane is not moving

Where did the speed go? The only way to have the treadmill moving is to have the plane move forward.

If you mean by the plane's wheels are rotating at 5MPH and the treadmill moving at 5MPH, then the actual location of the plane does not change, and unless there is wind blowing into the front of the aircraft, the plane is actually performing at 0 airspeed.

Airspeed is what determines the plane's flight performance and not the perception of the viewer from the ground. If the conveyor belt keeps going and the pilot cuts the engines, the plane will start moving backwards gradually and keep speeding up (backwards that is) until it matches the belt speed. Crank the engines again and it will reduce the backwards motion until it reaches par (meaning it looks still from afar.) When it reaches par and even more power is applied to the engine, the plane will visually move foward. Only then will there be any level of headwind. To take off, it's just a matter of the aircraft reaching the required takeoff headwind/airspeed, not how fast the wheels are spinning.

Headwind = what's shown on the airspeed indicator. Airspeed = direct relation to the performance of the aircraft.

The treadmill matches the speed of the plane's wheel. The wheels are not driven so the only way they would turn would be as a result of the plane moving forward.

The plane moves forward with RESPECT TO THE TREADMILL. If your reference frame "S" is in the treadmill being your ground, you will be moving. In this case, an object in reference frame S that is not moving (i.e. the treadmill is going backwards and the plane is glued to the treadmill), the object experiences airflow in the REVERSE direction. Now we know that S is moving backwards and the object is moving forward. Airflow is 0.

Try reference frame S' on the ground. The plane is not moving with respect to an observer on the ground, but the plane is moving with respect to the treadmill. However, AIR is not moving with respect to S', and nor is the plane. Thus air is not moving with respect to reference frame S'' (the plane). Thus there is no freaking airflow over the wings and thus there is no takeoff.

Relativity my friend. QED



Originally posted by: JMWarren
Originally posted by: InlineFour
Originally posted by: Kenazo
I recant my position... Given the original post's stipulations, it won't take off unless the thrust of the engine is greater than the mass of the airplane. otherwise it's going to stay there.

The OP:
The plane increases it's thrust and the wheels begin to rotate. The belt compensates for the rotation of the wheels in reverse, as in the belt moves in reverse exactly as fast as the wheels move forward.

The constraints set out by the scenario tell me it's not going to happen, unless the engine has more thrust than weight. Of course in real life there's no way this is going to happen.

that's what i keep thinking. the belt will always move in the same exact speed as the wheels.

i think we can simplify the question and say that, a plane is moving at 10mph and the conveyor belt is moving in reverse at 10mph, will the plane take off?


If the plane can fly at 10mph it will take off.

The treadmill moving backwords doesn't matter. The wheels isolate the body of the plane from the treadmill. The wheels will be rotating BACKWARDS at 20mph.

I don't know where you graduated from but if you read the problem, the treadmill moves as fast as the wheels do. There is no motion. You cant even throw out ANY numbers at all.

OK the trust of the engine moves the aiplane in relation to the air. Or whatever else the aiplane hapen to be standing on.
 

mugs

Lifer
Apr 29, 2003
48,920
46
91
Originally posted by: TankGuys
The bottom line here is that it depends on the wording of the question, and how people interpret it. There are some "wordings" where the plane won't take off, and some that the plane will take off.

The wording is fine. People always blame the wording and never back it up.

If people make the strict assuption that the treadmill moves backwards at the same speed as the wheels rotate forward, you run into issues of infinite acceleration and other fun stuff, and the plane won't take off.

Even if the speed of the wheels is infinite, the plane could take off.

If people assume the belt moves backward at a velocity equal to and opposite the plane's speed, then the plane takes off just fine, wheels spinning 2x the normal speed.

Correct, and good analogy (that I snipped out)
 

Slacker

Diamond Member
Oct 9, 1999
8,623
33
91
Nice, I have never heard this one before :D

The wording of the question allows for lots of assumptions and conclusion jumping. There are also details left out, like the conveyor being just as long as a runway would be, regardless, the plane propels itself forward until lift is created and the plane lifts off.
 

mugs

Lifer
Apr 29, 2003
48,920
46
91
Originally posted by: PurdueRy
Originally posted by: DLeRium
Originally posted by: PurdueRy
Originally posted by: InlineFour
purduery, you're saying that the plane will take off?

yes

So this is why I think my Purdue Engineering friend is incompetent. This is why we Cal students get the job.

Your assumption of 5MPH assumes that the wheels are spinning FASTER than the treadmill..... This is like walking at the same speed the treadmill is going. The treadmill is not at a fixed speed. It goes in reverse as fast as the wheel does.

Thus dv/dt = 0. Without any net motion there is no airflow, thus no takeoff.

http://www.straightdope.com/columns/060203.html

http://www.straightdope.com/columns/060303.html


Find something better to do than insulting someone's education

I love it. He insults your college and brags about his colllege, and you were right. Beautiful.
 

mugs

Lifer
Apr 29, 2003
48,920
46
91
Originally posted by: Slacker
Nice, I have never heard this one before :D

The wording of the question allows for lots of assumptions and conclusion jumping. There are also details left out, like the conveyor being just as long as a runway would be, regardless, the plane propels itself forward until lift is created and the plane lifts off.

All you need is the information in the problem and an understanding of physics. There are no assumptions or conclusions to be jumped to except incorrect ones.
 

Indolent

Platinum Member
Mar 7, 2003
2,128
2
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This is the stupidest, most pointless questions I've ever seen. I think the biggest confusion is that most people get the idea that the conveyor belt is similar to a gym treadmill. If someone would have just explained that the conveyor belt runway would have to be just as long as a regular runway, most people would understand that it would take off. It seems that the people saying it won't take off read the question as the airplane is not moving with respect to the ground next to the conveyor (as I also first thought).

edit* unless someone did explain this and I just missed it reading through this thread.
 

CallMeJoe

Diamond Member
Jul 30, 2004
6,938
5
81
As the aircraft applies thrust, it acquires airspeed and groundspeed simultaneously, moving forward relative to the entire conveyor assembly, not just the belt, as its tires start to turn. For the belt to turn "in reverse exactly as fast as the wheels move forward", the conveyor assembly would have to move forward with the same airspeed as the aircraft. The aircraft would lift off the belt as soon as it gained enough airspeed.
 

InlineFour

Banned
Nov 1, 2005
3,194
0
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tankguys i have an treadmill at home and will experiement with this in a minute. but i think you're forgetting that the conveyor belt can change speeds. it will match the speed of the wheels.