I got in on this thread too late....
Skoorb's question was an excellent one.
Friction has NOTHING to do with surface area. His example, sliding a brick on it's side will require an equal force as sliding it on its end (which has about half the surface area). Somewhere in this thread, someone was trying to calculate coefficients of friction, based on the tire size... Coefficients of friction:
..........................................Kinetic...Static
Rubber on concrete (dry)...0.68......0.90
Rubber on concrete (wet)..0.58
Rubber on asphalt (dry).....0.67......0.85
Rubber on asphalt (wet)....0.53
Rubber on ice.....................0.15
At this point in the discussion, the size of the tire DOES NOT MATTER AT ALL..
Now, I'll add that this is at the physics 1 level. The physics that likes to ignore all the extra factors that cause the real world to deviate from the nice equations.... such things as air resistance, etc.
Hopefully I can provide a decent explanation, slightly different than those above.
Skoorb... do you remember doing a lab on friction in high school? You would have noticed that rough sandpaper has a higher coefficient of friction than smooth sandpaper. Take two identical masses, one with rough sandpaper on the bottom, and the other with smooth sandpaper on the bottom. The rough one is harder to push. But why? The sandpaper is made out of the substance... (silicon carbide, or aluminum oxide, or garnet, or alumina-zirconia, or whatever). It's not just a matter of the coefficient of friction of the silicon carbide against the surface of the table......
In both cases, the surface area of the bottom of the block was the same, but the actual amount of surface in contact with the table changed. In the case of the rough sandpaper, the surface in contact decreased, causing an increased pressure per unit of area, increasing the degree to which the grit "dug in" to the table surface. At this point, the contact surfaces were not parallel to the direction of motion.
Now, I'm going out on a limb here, but I think in the case of the tires, there's a limit to the degree that the weight of the vehicle can "force the tire into the pavement." Increasing the pressure (decreasing the surface area with narrower tires) will not cause the rubber to be pushed farther into the irregular surface of the road. Thus, by making bigger tires, you can cause more of the coarse sandpaper analogy type of pushing into the road. I would have to guess that it is the edge of the treads that is doing the actual "digging in".
signed,
DrPizza, physics/math teacher.
p.s. I doubt that my explanation is perfect. But, at least to the degree that my students have to understand friction, in an ideal world that limits the amounts of extra interactions, I succeed in getting them that far.