Originally posted by: Gibsons
Originally posted by: cquark
Originally posted by: AnnihilatorX
The only known 100% efficient energy conversion right now though is matter-antimatter annihilation. That is really what E=mc^2 about. Pure mass -> Pure energy
Actually, matter-antimatter annihilation is only 100% efficient in cases which don't involve the strong force, such as electron-positron annihilation. The moment you begin dealing with the nucleus, events become more complex. For example, hydrogen-antihydrogen annhilation is only about 40% efficient, which is still quite impressive.
What happens to the other 60%? The reaction products from the hydrogen-antihydrogen would be some really high energy photons and.... ? Also, if the strong force is important here, would the efficiency change as we look at higher atomic number atom-antiatom pairs?
99% of the energy comes from proton-antiproton annhilation, which produces a variety of pions, including pi+'s, pi-'s, and pi0's. (NB: at high energies, you'll get a variety of more exotic particles, like we see in Crystal Barrel and other accelerator experiments, but that's not what we'd use to produce power and there are hundreds of possible reactions depending on the energy.)
Pi0's can decay into photons, but charge conservation forbids the pi+'s and pi-'s to do the same. As they're the lighest mesons, they can't decay into other mesons, so they decay into leptons: muons and muon antineutrinos. A few microseconds later, the muons decay into electrons, muon neutrinos, and electro antineutrinos. Conservation of energy and momentum require that most of the mass energy released be carried away by the neutrinos.
As neutrinos only interact through the weak force, they readily pass through normal matter (billions passed through you and the Earth beneath you as you read this sentence.) It would take several light years of lead to capture half the neutrinos in a beam, and as that would collapse into a black hole under its own weight, it's clear that you're not going to capture them for power production.
Increasing the atomic number would add proton-antineutron and antiproton-neutron interactions to the mix, along with pion-nucleon interactions, but none of them are noticeably more efficient, so I don't think that would help. It's also very difficult to construct antiatoms heavier than antihydrogen.