ShadowOfMyself
Diamond Member
- Jun 22, 2006
- 4,227
- 2
- 0
Originally posted by: mobobuff
You fail at probability.
Originally posted by: mobobuff
Yeah, you're probably right anyway.
What are the chances of him being right?
Originally posted by: mobobuff
You fail at probability.
Originally posted by: mobobuff
Yeah, you're probably right anyway.
Originally posted by: ShadowOfMyself
Originally posted by: mobobuff
You fail at probability.
Originally posted by: mobobuff
Yeah, you're probably right anyway.
What are the chances of him being right?![]()
Originally posted by: Whoozyerdaddy
Everyone knows girls aren't good at math. She probably thinks you're smart.
![]()
Originally posted by: So
Originally posted by: silverpig
Originally posted by: clickynext
Hmm, the chances of one person's birthday being on a particular day is 1 in 365. But for two to coincide like that, in some ways it makes sense for it to be the product of those? But then again, you could say that one person's birthday is already set, and the other person's has a 1 in 365 chance of being on that day.
??? *head explodes*
It's only (1/365)^2 if you ask what's the odds of having two people born on july 12th.
Neat! That's me.![]()
Originally posted by: silverpig
Originally posted by: So
Originally posted by: silverpig
Originally posted by: clickynext
Hmm, the chances of one person's birthday being on a particular day is 1 in 365. But for two to coincide like that, in some ways it makes sense for it to be the product of those? But then again, you could say that one person's birthday is already set, and the other person's has a 1 in 365 chance of being on that day.
??? *head explodes*
It's only (1/365)^2 if you ask what's the odds of having two people born on july 12th.
Neat! That's me.![]()
Heh. What are the odds huh?![]()
Originally posted by: fritolays
I told this girl that she has the same birthday as me... and I told her, "I heard the odds of that happening is like 1 in 300"
if you heard this from someone, would you think he was an idiot? haha
Originally posted by: ShadowOfMyself
The wiki article confirms the chance is only 100% at 366 people, obviously, since 365 people can still have a birthday in each day of the year, but the 366th will have to repeat someone elses'
Bah, both you and Wikipedia forgot about leap years. It is possible to assemble a crowd of 366 people ALL with different birthdays. You need 367 people to guarantee at least one repeat.Originally posted by: simms
1/366 to achieve 100% confidence that two people will have the same bday.
Originally posted by: simms
1/57 to get to 6 sigma...
1/366 to achieve 100% confidence that two people will have the same bday.
Originally posted by: dullard
Bah, both you and Wikipedia forgot about leap years. It is possible to assemble a crowd of 366 people ALL with different birthdays. You need 367 people to guarantee at least one repeat.Originally posted by: simms
1/366 to achieve 100% confidence that two people will have the same bday.
Doh, Aikouka beat me.
Originally posted by: LeiZaK
Originally posted by: simms
1/57 to get to 6 sigma...
1/366 to achieve 100% confidence that two people will have the same bday.
I don't think you can be 100% confident with only 366 people... you need 367 for that. The wiki is wrong.
edit: doh, Aikouka and dullard beat me. I'm slow today.
I didn't read the full article and assumed the [1] was a reference, not a note. Oh well, I still stand by my post that simms was technically wrong, but I'll edit the post above to reflect the wiki's simplification.Originally posted by: krotchy
notice the little 1 by their 1/366 = 100% thing.
It mentions at the bottom the leap year possibility.
Because there ARE years with more than 365 days, you need 367 people to provide 100% probability.Originally posted by: MrDudeMan
please explain how having more people than the number of days in a year, even if by 1, would not provide 100% probability. with the exception of years with more than 365 days, it would only take 366 people.
