stolen math joke

Page 3 - Seeking answers? Join the AnandTech community: where nearly half-a-million members share solutions and discuss the latest tech.

JujuFish

Lifer
Feb 3, 2005
11,398
1,029
136
Originally posted by: Savarak
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

lol, took me a sec to figure it out... it wasn't d/dx


i'm such a nerd to "get" it =/

You're not a nerd if you didn't get it at first.
 

Jeff7

Lifer
Jan 4, 2001
41,596
19
81
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

I don't know why, but I feel like crawling into a corner and dying right now.
 

Savarak

Platinum Member
Oct 27, 2001
2,718
1
81
Originally posted by: JujuFish
Originally posted by: Savarak
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

lol, took me a sec to figure it out... it wasn't d/dx


i'm such a nerd to "get" it =/

You're not a nerd if you didn't get it at first.

so i have a chance in this world afterall???