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stolen math joke

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Originally posted by: chuckywang
What does factorial have to do with this joke?
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for the love of god people...stop nit picking every detail. put whatever symbol you want in for factorial. it should be OBVIOUS it has nothing to do with the punchline. someone had to be invited to the party, so use delta if you it makes you feel better.
 
Originally posted by: Goosemaster
eh...that was awful.....
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no, it really wasnt. its corny, and funny for a nerdy joke. apples to oranges with non-nerdy jokes.

Originally posted by: puffff
punchline had little to do with the rest of the joke. could've been delivered better.
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do it then
 
Originally posted by: TheoPetro
Originally posted by: Jeff7
At least e^x would get constant attention!
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only if its an indef ingegral 🙂
Click to expand...

you are right, if it is an indefinite there is a constant added to e^x

however, there is a constant involved even if is a definite integral,
the integral itself is equal to constant (at least in terms of x)


 
Originally posted by: MrDudeMan
Originally posted by: Goosemaster
eh...that was awful.....
Click to expand...

no, it really wasnt. its corny, and funny for a nerdy joke. apples to oranges with non-nerdy jokes.

Originally posted by: puffff
punchline had little to do with the rest of the joke. could've been delivered better.
Click to expand...

do it then
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The host of a happenin' party noticed e^x was sitting alone in a corner, looking as if he wasn't enjoying himself. He went over to see what the problem was.

"What's wrong? Why don't you integrate yourself into the party?"

e^x replies, "I don't think it would do any good."

 
Originally posted by: puffff
Originally posted by: MrDudeMan
Originally posted by: Goosemaster
eh...that was awful.....
Click to expand...

no, it really wasnt. its corny, and funny for a nerdy joke. apples to oranges with non-nerdy jokes.

Originally posted by: puffff
punchline had little to do with the rest of the joke. could've been delivered better.
Click to expand...

do it then
Click to expand...

The host of a happenin' party noticed e^x was sitting alone in a corner, looking as if he wasn't enjoying himself. He went over to see what the problem was.

"What's wrong? Why don't you integrate yourself into the party?"

e^x replies, "I don't think it would do any good."
Click to expand...

but you left out all the other symbols 🙁


😀
 
wait a second...I thought I was right? no wait..I wasn't


int (e^x) = e ^x

e^x + c
------
e^x

c
-------- + 1=
e^x


this joke! (e^x)
---------------- = ! crap
c
 
Originally posted by: aux
Originally posted by: TheoPetro
Originally posted by: Jeff7
At least e^x would get constant attention!
Click to expand...

only if its an indef ingegral 🙂
Click to expand...

you are right, if it is an indefinite there is a constant added to e^x

however, there is a constant involved even if is a definite integral,
the integral itself is equal to constant (at least in terms of x)
Click to expand...
I have no idea what you just said.
 
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"
 
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"
Click to expand...
lol
 
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"
Click to expand...

I propose we lock & close the door.
Then incinerate the key.
 
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"
Click to expand...

lol, took me a sec to figure it out... it wasn't d/dx


i'm such a nerd to "get" it =/
 
Originally posted by: ItTheCow
I propose an alternate joke:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"
Click to expand...

now thats good...
 
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