• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Simple physics problem!

S

Syringer

Lifer
"a jet airliner moving initially at 736mph to the east where there is no wind moves into a region where the wind is blowing at 874mph in a direction 25* north of east. what is the new speed of the aircraft with respect to the ground? answer in units of mph."

So..my equation is: sqrt(sum x comps squared + sum y comps squared), which makes:

sqrt((cos 25*874 + 736)^2 + (sin 25*874)^2)

But that's not the right =/

What'd I do wrong?
 
you just add vetors so it is (874*sin25)j + (874cos25 736)i then convert to polar
ok got my calculator out 1572 at 14 degress north of east
 
First you need the horizontal component of the wind, which is 874cos(25), the vertical component of the wind is 874sin(25), but that is not important because that is not with respect to the ground.

So, then you add the 736 (initail speed) plus the wind factor, 874cos(25) to get 1528.113mph. (This is all assuming my answer is correct.)
 
Originally posted by: rgwalt
WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R
Click to expand...

First, the plane wouldn't fly initially because there is no wind. 😕
 
You must log in or register to reply here.

TRENDING THREADS

Back
Top