Simple physics problem!

[Syringer]

"a jet airliner moving initially at 736mph to the east where there is no wind moves into a region where the wind is blowing at 874mph in a direction 25* north of east. what is the new speed of the aircraft with respect to the ground? answer in units of mph."

So..my equation is: sqrt(sum x comps squared + sum y comps squared), which makes:

sqrt((cos 25*874 + 736)^2 + (sin 25*874)^2)

But that's not the right =/

What'd I do wrong?

 

[JetBlack69]

1528.113 mph.

 

[freakflag]

The answer is....4??

 

[Yossarian451]

you just add vetors so it is (874*sin25)j + (874cos25 736)i then convert to polar
ok got my calculator out 1572 at 14 degress north of east

 

[Syringer]

Did you use my equation for that?

 

[JetBlack69]

First you need the horizontal component of the wind, which is 874cos(25), the vertical component of the wind is 874sin(25), but that is not important because that is not with respect to the ground.

So, then you add the 736 (initail speed) plus the wind factor, 874cos(25) to get 1528.113mph. (This is all assuming my answer is correct.)

 

[rgwalt]

WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R

 

[JetBlack69]

Originally posted by: rgwalt
WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R

First, the plane wouldn't fly initially because there is no wind.

 

[Mingon]

You should realy have its height to be truly accurate

 

[her209]

Originally posted by: JetBlack69

Originally posted by: rgwalt
WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R

First, the plane wouldn't fly initially because there is no wind.

Yep!

 

[dighn]

did you just enter it into the calculator incorrectly? the equation looks fine to me

 

[Chaotic42]

874 mph? Holy Christmas, Batman.