Simple physics problem!

Syringer

Lifer
"a jet airliner moving initially at 736mph to the east where there is no wind moves into a region where the wind is blowing at 874mph in a direction 25* north of east. what is the new speed of the aircraft with respect to the ground? answer in units of mph."

So..my equation is: sqrt(sum x comps squared + sum y comps squared), which makes:

sqrt((cos 25*874 + 736)^2 + (sin 25*874)^2)

But that's not the right =/

What'd I do wrong?

1528.113 mph.

Yossarian451

Senior member
you just add vetors so it is (874*sin25)j + (874cos25 736)i then convert to polar
ok got my calculator out 1572 at 14 degress north of east

Syringer

Lifer
Did you use my equation for that?

JetBlack69

Diamond Member
First you need the horizontal component of the wind, which is 874cos(25), the vertical component of the wind is 874sin(25), but that is not important because that is not with respect to the ground.

So, then you add the 736 (initail speed) plus the wind factor, 874cos(25) to get 1528.113mph. (This is all assuming my answer is correct.)

rgwalt

Diamond Member
WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R

JetBlack69

Diamond Member
Originally posted by: rgwalt
WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R

First, the plane wouldn't fly initially because there is no wind.

Mingon

Diamond Member
You should realy have its height to be truly accurate

her209

No Lifer
Originally posted by: JetBlack69
Originally posted by: rgwalt
WTF kind of crazy wind is this plane flying into?!? 874MPH? Is this plane flying on Jupiter?

R
First, the plane wouldn't fly initially because there is no wind.
Yep!

dighn

Lifer
did you just enter it into the calculator incorrectly? the equation looks fine to me

Chaotic42

Lifer
874 mph? Holy Christmas, Batman.