riddle....no one i know can figure this out

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HonkeyDonk

Diamond Member
Oct 14, 2001
4,020
0
0
Originally posted by: ShadowBlade
Originally posted by: HonkeyDonk
the original version words it much clearer than that and still retains the mysterious "where did the $1 go?" effect.

I have no means of getting the original version....a friend told me it a few days ago, so thats from memory from his memory. If youve got the original, post it.

Well, from the top of my head, it goes something like:

3 men stop by a hotel to rent a room for the night. The rate is $30/room so they all pay $10 each. However, when the 3 went up to their room, the manager forgot that there's a special and the room is only $25. So he gives $5 to the bellboy and he goes up to the room to return the $5.

The bellboy however, thinking he is clever, decides to pocket $2 for himself and return $3 to the 3 men.

So now, each person has essentially paid $9 for a total of $27 and the bellboy has $2. So where did the other $1 go?
 

Aztech

Golden Member
Jan 19, 2002
1,922
0
0
Originally posted by: HajikuFlip
Originally posted by: ShadowBlade
math ppl, i dont care if this is really obvious, but tell me the answer
Three guys go into a hotel and a room for all three of them costs $25 a night.
They only need to stay for one night.
They dont want to split $25 into 3, so they each pay $10 and go up to their room.
The hotel owner doesnt want to keep their $5 change, so he sends a bell boy up to their room to give it to them.
The bell boy doesnt want to split $5 into 3, so he keeps $2 and gives each of them $1.
Now each of them, after getting their change payed $9. $9 x 3 is $27, + the bell boy's $2 is $29.
Where is the last dollar?

$9x3 = $27 + the $3 they got back = $30.


The question is worded tricky and leads people into doing faulty math.

Edit Huh? What about the bell boy's $2?
 

Iron Woode

Elite Member
Super Moderator
Oct 10, 1999
31,200
12,735
136
Originally posted by: ShadowBlade
math ppl, i dont care if this is really obvious, but tell me the answer
Three guys go into a hotel and a room for all three of them costs $25 a night.
They only need to stay for one night.
They dont want to split $25 into 3, so they each pay $10 and go up to their room.
The hotel owner doesnt want to keep their $5 change, so he sends a bell boy up to their room to give it to them.
The bell boy doesnt want to split $5 into 3, so he keeps $2 and gives each of them $1.
Now each of them, after getting their change payed $9. $9 x 3 is $27, + the bell boy's $2 is $29.
Where is the last dollar?
Your math is in error.

They paid $25, and each got $1 back. That equals $28. The bell-boy pockets $2 and that equals $30.

Edit: the sad part is that a vital portion of the joke is missing. The room initially cost $30, but the price was wrong and it is realy $25.

 

Aztech

Golden Member
Jan 19, 2002
1,922
0
0
Originally posted by: Iron Woode
Originally posted by: ShadowBlade
math ppl, i dont care if this is really obvious, but tell me the answer
Three guys go into a hotel and a room for all three of them costs $25 a night.
They only need to stay for one night.
They dont want to split $25 into 3, so they each pay $10 and go up to their room.
The hotel owner doesnt want to keep their $5 change, so he sends a bell boy up to their room to give it to them.
The bell boy doesnt want to split $5 into 3, so he keeps $2 and gives each of them $1.
Now each of them, after getting their change payed $9. $9 x 3 is $27, + the bell boy's $2 is $29.
Where is the last dollar?
Your math is in error.

They paid $25, and each got $1 back. That equals $28. The bell-boy pockets $2 and that equals $30.

Winnar!
 

yoda291

Diamond Member
Aug 11, 2001
5,079
0
0
3x9 = 27. If you add the 3 dollars that the bellboy gave back, that makes 30 essentially meaning 3x10. What the bellboy is holding is their change, not the difference.
 

AreaCode707

Lifer
Sep 21, 2001
18,447
133
106
Originally posted by: HonkeyDonk
Originally posted by: ShadowBlade
Originally posted by: HonkeyDonk
the original version words it much clearer than that and still retains the mysterious "where did the $1 go?" effect.

I have no means of getting the original version....a friend told me it a few days ago, so thats from memory from his memory. If youve got the original, post it.

Well, from the top of my head, it goes something like:

3 men stop by a hotel to rent a room for the night. The rate is $30/room so they all pay $10 each. However, when the 3 went up to their room, the manager forgot that there's a special and the room is only $25. So he gives $5 to the bellboy and he goes up to the room to return the $5.

The bellboy however, thinking he is clever, decides to pocket $2 for himself and return $3 to the 3 men.

So now, each person has essentially paid $9 for a total of $27 and the bellboy has $2. So where did the other $1 go?

Ah, I like that wording better.

They did each pay $9 for a total of $27. The hotel owner has $25 of the $27, the bellboy has $2 of the $27, and each guy has $1, totalling $30.

If you look at the original line:
Now each of them, after getting their change payed $9. $9 x 3 is $27, + the bell boy's $2 is $29.

Yep, they each paid $9, for a total of $27, and then they each have a dollar left. You can't add the bellboy's $2 because you've already added that in.
 

Iron Woode

Elite Member
Super Moderator
Oct 10, 1999
31,200
12,735
136
Originally posted by: yoda291
3x9 = 27. If you add the 3 dollars that the bellboy gave back, that makes 30 essentially meaning 3x10. What the bellboy is holding is their change, not the difference.
You are wrong, completely wrong.

$25 for the room. $3 is given back = $28. The bell-boy pocketed $2. $28+$2=$30.

 

ShadowBlade

Diamond Member
Feb 11, 2005
4,263
0
0
Originally posted by: HotChic
Yep, they each paid $9, for a total of $27, and then they each have a dollar left. You can't add the bellboy's $2 because you've already added that in.

so then wheres the other $3???

 

Iron Woode

Elite Member
Super Moderator
Oct 10, 1999
31,200
12,735
136
Originally posted by: ShadowBlade
Originally posted by: HotChic
Yep, they each paid $9, for a total of $27, and then they each have a dollar left. You can't add the bellboy's $2 because you've already added that in.

so then wheres the other $3???
read my 2 replies for the correct answer.
 

amol

Lifer
Jul 8, 2001
11,679
1
0
Originally posted by: ShadowBlade
Originally posted by: HotChic
Yep, they each paid $9, for a total of $27, and then they each have a dollar left. You can't add the bellboy's $2 because you've already added that in.

so then wheres the other $3???

OMG, do you NOT understand?

They paid $30 . . .

The manager kept $25, gave the bellboy $5. 25+5=30

The bellboy kept $2 and the gave the men $3. 3+2=5

The question is worded in a fuzzy way
 

her209

No Lifer
Oct 11, 2000
56,336
11
0
Originally posted by: ShadowBlade
Originally posted by: HotChic
Yep, they each paid $9, for a total of $27, and then they each have a dollar left. You can't add the bellboy's $2 because you've already added that in.
so then wheres the other $3???
OMG.

Think of the room as costing $27 (ie, $25+$2). Then each of them got $1 back. The total adds up to $30. Get it!?
 

yoda291

Diamond Member
Aug 11, 2001
5,079
0
0
Originally posted by: Iron Woode
Originally posted by: yoda291
3x9 = 27. If you add the 3 dollars that the bellboy gave back, that makes 30 essentially meaning 3x10. What the bellboy is holding is their change, not the difference.
You are wrong, completely wrong.

$25 for the room. $3 is given back = $28. The bell-boy pocketed $2. $28+$2=$30.

Fool! you just repeated what I just said backwards.
They paid 3x10. the bellboy gave back 1 dollars each making it 3x9. They are still owed 2 dollars change for a 25 dollar room, which the bellboy is holding.
 

Philippine Mango

Diamond Member
Oct 29, 2004
5,594
0
0
All you have to do is ignore the part with the multiplication and addition then do the math on your own. There is no extra dollar, this was a fairly simple problem and the "math" your told is designed to confuse you so just do it all in your head and it will work out..
 

Iron Woode

Elite Member
Super Moderator
Oct 10, 1999
31,200
12,735
136
Originally posted by: yoda291
Originally posted by: Iron Woode
Originally posted by: yoda291
3x9 = 27. If you add the 3 dollars that the bellboy gave back, that makes 30 essentially meaning 3x10. What the bellboy is holding is their change, not the difference.
You are wrong, completely wrong.

$25 for the room. $3 is given back = $28. The bell-boy pocketed $2. $28+$2=$30.

Fool! you just repeated what I just said backwards.
They paid 3x10. the bellboy gave back 1 dollars each making it 3x9. They are still owed 2 dollars change for a 25 dollar room, which the bellboy is holding.
You are still wrong.

They paid $30. Room was really $25. $5 is to be given back. Each man gets $1. That is $28. The bell-boy keeps $2. That is $30.

your method equals $29 not $30. You are thinking of removing 1 dollar for ech man from 10. This is $27 by your method. Bellboy still has $2. This is only $29.

Your math is in error.

Face it, you've been PWNED.
 

jdub1107

Golden Member
Feb 9, 2003
1,060
0
0
You can't use $27, since the manager is returning $5. Your method would make a total of $32. It's $25 divided by 3 and then add the $1 for each person and the $2 that the bellboy stole.
 

dethman

Lifer
Oct 12, 1999
10,263
3
76
complaining everyone is pissy when everybody understands except you even though it's been explained 10 times???