Quick math question: E * E^-1 is 1?

[yllus]

Basically I have two questions to answer in a take-home test. Please see the below image and post if you have any help to offer. 🙂

http://degenerates.org/temp/rel_ops.jpg

 

[MartyMcFly3]

Dont mind me, i just laughed at "linear anal."

 

[Howard]

uh, E^-1 = 1/E, therefore E * 1/E = 1.

 

[George P Burdell]

(E^a)*(E^b) = E^(a+b)
a=1
b=-1
therefore E^(a+b) = E^0 = 1

for example, http://www.google.com/search?q=exp%281%29*exp%28-1%29

edit for bad linkage

 

[Pepsi90919]

Talking difference operators in linear anal.

stick out your butt? :shocked:

 

[TuxDave]

Wrong.. it's equal to the determinant of an identity matrix. 😛

 

[George P Burdell]

Originally posted by: TuxDave
Wrong.. it's equal to the determinant of an identity matrix.

/bows down in respect

 

[chuckywang]

I think his question is just a little bit more sophisticated than simple algebra.

 

[JonnyStarks]

Originally posted by: MartyMcFly3
Dont mind me, i just laughed at "linear anal."

😀

 

[TuxDave]

Originally posted by: chuckywang
I think his question is just a little bit more sophisticated than simple algebra.

Most likely.. but I don't remember what difference operators in linear analysis meant.