Prove the Following:

JPS35

Senior member
Apr 9, 2006
890
83
91
F(B5) = {[(New BSG)^2 + (SW 4+5+6) + cos(SG1)}] / √[(SW 1+2+3 )] + (ST:TOS+TNG)} - lim┬(n→∞)〖ST:V〗{tan[(ST: DS9) - (SGU/SGA)]} / {BSG:TOS + log_2〖(ST:E〗)}

iff

B5 ≥ New BSG ≥ SW 4+5+6 ≥ SG1 ≥ SW 1+2+3 ≥ ST:TOS+TNG

And

SW 1+2+3 > ST: DS9 > SG:U > BSG:TOS > ST:E > SG:A

And

lim┬(n→∞)〖ST:V〗≠ 0
 

phucheneh

Diamond Member
Jun 30, 2012
7,306
5
0
Was there time travel in Voyager? I don't remember. I must have been distracted by all the sucking.
 

Paratus

Lifer
Jun 4, 2004
17,551
15,638
146
I don't know shit about maths, but the new Battlestar Galactica sucked ass.

Laura-Roslin-Mary-McDonnel-Battle-Star-Galactica.jpeg
 

Nograts

Platinum Member
Dec 1, 2014
2,534
3
0
The answer to all of life's problems can be solved with one of three solutions:

1) 7
2) Bill Murray
3) Alcohol

I choose Bill Murray for this situation.
 

Captante

Lifer
Oct 20, 2003
30,348
10,868
136
F(B5) = {[(New BSG)^2 + (SW 4+5+6) + cos(SG1)}] / √[(SW 1+2+3 )] + (ST:TOS+TNG)} - lim┬(n→∞)〖ST:V〗{tan[(ST: DS9) - (SGU/SGA)]} / {BSG:TOS + log_2〖(ST:E〗)}

iff

B5 ≥ New BSG ≥ SW 4+5+6 ≥ SG1 ≥ SW 1+2+3 ≥ ST:TOS+TNG

And

SW 1+2+3 > ST: DS9 > SG:U > BSG:TOS > ST:E > SG:A

And

lim┬(n→∞)〖ST:V〗≠ 0



That might as well be hieroglyphics as far as I'm concerned. :confused:
 

master_shake_

Diamond Member
May 22, 2012
6,425
292
121
F(B5) = {[(New BSG)^2 + (SW 4+5+6) + cos(SG1)}] / √[(SW 1+2+3 )] + (ST:TOS+TNG)} - lim┬(n→∞)〖ST:V〗{tan[(ST: DS9) - (SGU/SGA)]} / {BSG:TOS + log_2〖(ST:E〗)}

iff

B5 ≥ New BSG ≥ SW 4+5+6 ≥ SG1 ≥ SW 1+2+3 ≥ ST:TOS+TNG

And

SW 1+2+3 > ST: DS9 > SG:U > BSG:TOS > ST:E > SG:A

And

lim┬(n→∞)〖ST:V〗≠ 0

i get it!

i think....

42.

you're welcome.
 

SKORPI0

Lifer
Jan 18, 2000
18,471
2,411
136
F(B5) = {[(New BSG)^2 + (SW 4+5+6) + cos(SG1)}] / √[(SW 1+2+3 )] + (ST:TOS+TNG)} - lim┬(n→∞)〖ST:V〗{tan[(ST: DS9) - (SGU/SGA)]} / {BSG:TOS + log_2〖(ST:E〗)}

iff

B5 ≥ New BSG ≥ SW 4+5+6 ≥ SG1 ≥ SW 1+2+3 ≥ ST:TOS+TNG

And

SW 1+2+3 > ST: DS9 > SG:U > BSG:TOS > ST:E > SG:A

And

lim┬(n→∞)〖ST:V〗≠ 0

--------------------------------------------------

Substituting the IMDb ratings for each show.

B5 = 8.2

BSG:TOS= 8.8
NBSG = 8.8

SW 4+5+6 = 8.7+8.8+8.4 = 25.9
SW 1+2+3 = 6.6+6.8+7.7 = 21.1

ST:TOS = 8.4
ST:TNG = 8.7
ST:V = 7.7
ST:DS9 = 7.9
ST:E = 7.5

SG1 = 8.5
SGU = 7.7
SGA = 8.1
------------------
F(8.2) = {[(8.8)^2 + (25.9) + cos(8.5)}] / √[(21.1 )] + (17.1)} - lim┬(n→∞)〖7.7〗{tan[(7.9) - (7.7/8.1)]} / {8.8 + log_2〖(7.7〗)}

iff

8.2 ≥ 8.8 ≥ 25.9 ≥ 8.5 ≥ 21.1 ≥ 17.1 :confused:

And

21.1 > 7.9 >7.7 > 8.8 > 7.5 > 8.1 :confused:

And

lim┬(n→∞)〖7.7〗≠ 0 :confused:
===================
Still confused....
 
Last edited:

maniacalpha1-1

Diamond Member
Feb 7, 2010
3,562
14
81
B5 ≥ ds9 ≥ bsg ≥ sg1 ≥ sg:a ≥ sw 4,5,6 ≥tng > sw 1,2,3, >st:e >sgu > st tos > bsg tos