Prove the Following:

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Mar 16, 2005
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2 + (- sqrt(1- x^2- (y- abs(x))^2))cos(30((2-x^2-(y-abs(x))^2))), x is from -1 to 1, y is from -1 to 1.5, z is from 1 to 2
 

TheVrolok

Lifer
Dec 11, 2000
24,254
4,092
136
Was there time travel in Voyager? I don't remember. I must have been distracted by all the sucking.
Not a whole lot from what I remember. Shattered and Relativity were sorta time travel. That one episode with Kes, too?


Was a bit of a troll post originally, but I do agree with what someone earlier said; there were a few really good Voyager episodes tucked into an otherwise unwatchable series.
 

Ruptga

Lifer
Aug 3, 2006
10,246
207
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Not a whole lot from what I remember. Shattered and Relativity were sorta time travel. That one episode with Kes, too?

Also Year of Hell 1 and 2, Timeless, and Future's End 1 and 2, at least. Some of those were good episodes, but ultimately I think time travel was just a convenient crutch to fall back on, a final final frontier they could explore rather than coming up with fresh stories or developing characters.
 

JPS35

Senior member
Apr 9, 2006
890
83
91
B5 ≥ ds9 ≥ bsg ≥ sg1 ≥ sg:a ≥ sw 4,5,6 ≥tng > sw 1,2,3, >st:e >sgu > st tos > bsg tos

HEAVENS TO MURGATROYD, Man! Is this remedial math the product of Common Core educational standards? Perhaps Math 48 at a local Community College might help? To believe that DS9 is that high, even above bsg and sg1...(shakes head in disbelief).
 

TheVrolok

Lifer
Dec 11, 2000
24,254
4,092
136
Also Year of Hell 1 and 2, Timeless, and Future's End 1 and 2, at least. Some of those were good episodes, but ultimately I think time travel was just a convenient crutch to fall back on, a final final frontier they could explore rather than coming up with fresh stories or developing characters.
I didn't consider Year From Hell traditional time travel for some reason, but totally forgot about Future's End (how could I forget that fancy Sarah silverman work?) and Timeless.
 

Fenixgoon

Lifer
Jun 30, 2003
33,286
12,849
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F(B5) = {[(New BSG)^2 + (SW 4+5+6) + cos(SG1)}] / √[(SW 1+2+3 )] + (ST:TOS+TNG)} - lim┬(n→∞)〖ST:V〗{tan[(ST: DS9) - (SGU/SGA)]} / {BSG:TOS + log_2〖(ST:E〗)}

iff

B5 ≥ New BSG ≥ SW 4+5+6 ≥ SG1 ≥ SW 1+2+3 ≥ ST:TOS+TNG

And

SW 1+2+3 > ST: DS9 > SG:U > BSG:TOS > ST:E > SG:A

And

lim┬(n→∞)〖ST:V〗≠ 0

burn him at the stake!
 

maniacalpha1-1

Diamond Member
Feb 7, 2010
3,562
14
81
HEAVENS TO MURGATROYD, Man! Is this remedial math the product of Common Core educational standards? Perhaps Math 48 at a local Community College might help? To believe that DS9 is that high, even above bsg and sg1...(shakes head in disbelief).

Those first ones are all pretty damn close, but we've all committed a great crime, me included...I don't see any mention of Firefly. There's probably several other honorable mentions that should have been included in these formulas.
 

phucheneh

Diamond Member
Jun 30, 2012
7,306
5
0
Anybody crack them wormhole equations yet?

kt7VnNo.jpg
 

JPS35

Senior member
Apr 9, 2006
890
83
91
Quote:
Originally Posted by JPS35
HEAVENS TO MURGATROYD, Man! Is this remedial math the product of Common Core educational standards? Perhaps Math 48 at a local Community College might help? To believe that DS9 is that high, even above bsg and sg1...(shakes head in disbelief).

Those first ones are all pretty damn close, but we've all committed a great crime, me included...I don't see any mention of Firefly. There's probably several other honorable mentions that should have been included in these formulas.

Firefly was considered, but then you have to throw in other anomalies such as BR25thC, FS, LIS, Lex, and others. These may just be tangential anomalies.
 

JPS35

Senior member
Apr 9, 2006
890
83
91
--------------------------------------------------

Substituting the IMDb ratings for each show.

B5 = 8.2

BSG:TOS= 8.8
NBSG = 8.8

SW 4+5+6 = 8.7+8.8+8.4 = 25.9
SW 1+2+3 = 6.6+6.8+7.7 = 21.1

ST:TOS = 8.4
ST:TNG = 8.7
ST:V = 7.7
ST:DS9 = 7.9
ST:E = 7.5

SG1 = 8.5
SGU = 7.7
SGA = 8.1
------------------
F(8.2) = {[(8.8)^2 + (25.9) + cos(8.5)}] / √[(21.1 )] + (17.1)} - lim┬(n→∞)〖7.7〗{tan[(7.9) - (7.7/8.1)]} / {8.8 + log_2〖(7.7〗)}

iff

8.2 ≥ 8.8 ≥ 25.9 ≥ 8.5 ≥ 21.1 ≥ 17.1 :confused:

And

21.1 > 7.9 >7.7 > 8.8 > 7.5 > 8.1 :confused:

And

lim┬(n→∞)〖7.7〗≠ 0 :confused:
===================
Still confused....

You are close, but I think I can help clear the confusion. If you use the IMDb ratings system you need to convert for time dilation (red/blue shift).

Although it is conceivable, based on the original equation, that B5 ≥ New BSG; it is also true that B5 and New BSG > BSG:TOS

Similarly, in order for ST:TOS and ST:TNG ≥ B5 would mean that B5 = √-(B5) or (b5)i. You might as well try to divide by 0 in that case.

I've also considered using RT ratings, but I am not sure you can mix terms that way. If so, you might need to use a non-Euclidian Geometry (Projective Geometry?).
 

Paladin3

Diamond Member
Mar 5, 2004
4,933
878
126
F(B5) = {[(New BSG)^2 + (SW 4+5+6) + cos(SG1)}] / √[(SW 1+2+3 )] + (ST:TOS+TNG)} - lim┬(n→∞)〖ST:V〗{tan[(ST: DS9) - (SGU/SGA)]} / {BSG:TOS + log_2〖(ST:E〗)}

iff

B5 ≥ New BSG ≥ SW 4+5+6 ≥ SG1 ≥ SW 1+2+3 ≥ ST:TOS+TNG

And

SW 1+2+3 > ST: DS9 > SG:U > BSG:TOS > ST:E > SG:A

And

lim┬(n→∞)〖ST:V〗≠ 0

*reads through equation*

"It never occurred to me to think of space as the thing that was moving!"