- Aug 30, 2004
- 2,519
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Originally posted by: Schfifty Five
Originally posted by: ManyBeers
Originally posted by: Schfifty Five
Originally posted by: ManyBeers
Originally posted by: txrandom
Originally posted by: ManyBeers
Originally posted by: txrandom
( 13 choose 1) * (4 choose 3) * (12 choose 2) * (4 choose 1) * (4 choose 1).
This doesn't include 4 of a kinds or full houses.
Edit: This also assumes that all 52 cards have an even chance to be drawn. Obviously cards that are already dealt to the players will have a lower chance of showing up.
Look i am using peoples responses on here to double check my self, so if you don't mind would you please give an answer and not a formula.
Look i am just trying to help you, but now I won't.
Well, i don't understand why you just didn't answer the question if you knew the answer.
maybe b/c the way you asked him made it sound like you were demanding it rather than kindly asking.
Furthermore, if you bothered to put even a little effort, you could have done the calculation yourself given what txrandom gave you, but you're jsut one lazy person.
You think i am asking on here because i would understand his formula?
It's like if someone tells you "the answer is 5*5", and you reply with "C'mon, just give me the answer". Are you that lazy to solve 5*5?
Now granted, I don't know the answer to your original question and I also do not know if Txrandom's equation is the correct answer, however, your laziness is what makes you sound stupid and a child.
Look up how to do (X choose Y) type problems (permutation/combination formulas) and you will be able to sovle TXrandom's answer in a jiffy.
lol 54 years old.
Go play in another thread i don't need or want your advice or your continued insults. You are a typical big-mouth internet coward, who hides behind his computer and throws barbs at other posters. Now get lost.