log ((x+90)/x) - 2 = log (x/(x+90))
This is simply the equation you need to solve the problem that comes from the information that was given in the problem
"The logarithim of a rational number exceeds the logarithim of it's reciprocal by two, and it's numerator is 90 more than the denominator. Find the rational number."
log (x+90) - log x - 2 = log x - log (x+90)
Since log (a/b) = log a - log b, the logs with the fractions were separated
2 log (x+90) - 2 log x = 2
log (x+90) and 2 were added to both sides, and log x was subtracted from both sides to simplify the equation
log (x+90) - log x = 1
Both sides of the equation were divided by 2 to simplify
log ((x+90)/x) = 1
Again, log(a/b) = log a - log b was used, but this time to combine the logs into 1 log
(x+90)/x = 10
Since log 10 = 1, (x+90)/x = 10 must be true
x + 90 = 10 x
9 x = 90
x = 10
This was the solution to the equation (x+90)/x = 10
(x+90)/x = 100/10
Since x = 10, 10 was substituted for x in the equation
-Tom
This is simply the equation you need to solve the problem that comes from the information that was given in the problem
"The logarithim of a rational number exceeds the logarithim of it's reciprocal by two, and it's numerator is 90 more than the denominator. Find the rational number."
log (x+90) - log x - 2 = log x - log (x+90)
Since log (a/b) = log a - log b, the logs with the fractions were separated
2 log (x+90) - 2 log x = 2
log (x+90) and 2 were added to both sides, and log x was subtracted from both sides to simplify the equation
log (x+90) - log x = 1
Both sides of the equation were divided by 2 to simplify
log ((x+90)/x) = 1
Again, log(a/b) = log a - log b was used, but this time to combine the logs into 1 log
(x+90)/x = 10
Since log 10 = 1, (x+90)/x = 10 must be true
x + 90 = 10 x
9 x = 90
x = 10
This was the solution to the equation (x+90)/x = 10
(x+90)/x = 100/10
Since x = 10, 10 was substituted for x in the equation
-Tom