Originally posted by: fuzzybabybunny
Originally posted by: punchkin
Originally posted by: fuzzybabybunny
Originally posted by: punchkin
Incorrect. It will capture much less, because there is less surface area.
Explain this surface area thing.
The sensor is one quarter the size of a full-frame sensor. Hence it collects one quarter the light.
The relation for exposure and aperture is this:
N^2 / t = LS / L
N is the f-number
t is the exposure time
L is the scene's luminance
S is the ISO speed
K is the light meter's calibration constant
Note that none of the variables have anything to do with sensor size or sensor area.
But let's do some thought games also.
You have a 50mm f/2.8. By your definition, if you slap this onto a small digicam with a "crop factor" sensor of 5x, you'll basically be running around with a nearly unusably dark f/16 lens? So if a FF SLR with this lens can take a picture using 1/200s, this same lens on a 5x sensor would need a shutter speed of 1/6 second to get the same exposure as the FF SLR?