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Obtaining a universal reference frame using time.

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Ben90

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Lets have three observers: ClockA, ClockB, and Earth. Shoot the clocks off in directions in which gravitational forces are the same for both clocks. The clocks then relay their time to Earth, and the one whose time has passed the most is closer to a standstill. Rinse and repeat.
 
Lets have three observers: ClockA, ClockB, and Earth. Shoot the clocks off in directions in which gravitational forces are the same for both clocks. The clocks then relay their time to Earth, and the one whose time has passed the most is closer to a standstill. Rinse and repeat.

There is no universal frame of reference, it's all relative. In clockA's frame of reference it is not moving, in earth's frame of reference clockA will have a speed. The velocity depends on the frame of reference you choose.
 
I don't have a clue what you are trying to propose, but Paul98's reply is right and disproves your theory regardless.
 
Universal time reference per today's scientists, is the instant of the Big Bang, is is not?

(until that theory is superseded).
 
There is no universal frame of reference, it's all relative. In clockA's frame of reference it is not moving, in earth's frame of reference clockA will have a speed. The velocity depends on the frame of reference you choose.

This.

Their being shot off mimics gravity and is part of it. What's done with their info that is sent back depends on when they shoot the info back (according to their own clock) and how far it has to go to be received. You're missing a lot of things and don't actually seem to have a question. In fact, is the original post a question, a solution to something, what?
 
There is no universal frame of reference, it's all relative. In clockA's frame of reference it is not moving, in earth's frame of reference clockA will have a speed. The velocity depends on the frame of reference you choose.

There may very well be. It's the frame in which the dipole term of the CMB is zero.
 
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