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**new homework Question**

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<< NEW:
an easter egg basket contains 5 red and 3 blue eggs. 4 eggs are drawn at random without replacement. how many ways are there to choose wthe following?

1) all red eggs
2) all green eggs
3) 2 of each
4) 3 re d and 1 blue
>>



4 red
3 red 1 blue
2 red 2 blue
1 red 3 blue

[edit]Oh lol n/m, I thought it was just asking for possible combos.

2) all green = 0 chance 😀
 


<<

<< NEW: an easter egg basket contains 5 red and 3 blue eggs. 4 eggs are drawn at random without replacement. how many ways are there to choose wthe following? 1) all red eggs 2) all green eggs 3) 2 of each 4) 3 re d and 1 blue >>

4 red 3 red 1 blue 2 red 2 blue 1 red 3 blue
>>

unable to comprehend the response.
 
1) 5/8 * 4/7 * 3/6 * 2/5 = too lazy to calculate
2) ??
3) 4) much more complicated..... don't feel like answering
 
Just disregard my response. I was OK in prob & stat up to the point where the answer was no longer intuitive, then I crashed.
 
just realized that i misread the question...
and the question's a bit too vague to answer, or it's almost trivial
 
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