Mythbusters to take on "the plane and the treadmill" conundrum?

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Poulsonator

Golden Member
Aug 19, 2002
1,597
0
76
Originally posted by: ScottMac
OK, I read the whole thread. I'm amazed.

There was almost the right thing posted once ... the missing explanation:

You (non take-offers) are on a skateboard, which is located on a treadmill. You have a rope around your waist that is attached to a '57 Chevy's rear bumper.

Begin: the car is stationary. The treadmill starts up moving however fast you want it to go. The rope tightens and you remain stationary on the treadmill, relative to the surrounding air. The skateboard wheels match the speed of the treadmill belt.

Later: The greaser sitting at the wheel of the '57 Chevy (327, blower, pipes, upper/lower work) pops the clutch and zooms off to the burger stand. The rope will pull you off the front of the treadmill (trust me). Even if the treadmill speeds up to match the speed of the wheels on your skateboard, the rope (which would correspond to the prop of an airplane as a motivational force) is going to pull you forward and off the front of the treadmill. Your "airspeed" - how fast you are going relative to the surrounding air - will increase.

Later still: The Greaser gets a cheesburger, fires, and malt *and* a date with Suzy the Cheerleader.... and you end up looking like Grandma's dog in Lampoon's Summer Vacation movie.

Disclaimer: *Never* tie yourself to the bumper of a car, especially a '57 Chevy driven by a hungry Greaser, with out without a skateboard ...

FWIW

For those "non-taker-offers", what's your take on this? This is the best example used in the thread yet on why the plane would take off.
 

smack Down

Diamond Member
Sep 10, 2005
4,507
0
0
Originally posted by: Poulsonator
Originally posted by: ScottMac
OK, I read the whole thread. I'm amazed.

There was almost the right thing posted once ... the missing explanation:

You (non take-offers) are on a skateboard, which is located on a treadmill. You have a rope around your waist that is attached to a '57 Chevy's rear bumper.

Begin: the car is stationary. The treadmill starts up moving however fast you want it to go. The rope tightens and you remain stationary on the treadmill, relative to the surrounding air. The skateboard wheels match the speed of the treadmill belt.

Later: The greaser sitting at the wheel of the '57 Chevy (327, blower, pipes, upper/lower work) pops the clutch and zooms off to the burger stand. The rope will pull you off the front of the treadmill (trust me). Even if the treadmill speeds up to match the speed of the wheels on your skateboard, the rope (which would correspond to the prop of an airplane as a motivational force) is going to pull you forward and off the front of the treadmill. Your "airspeed" - how fast you are going relative to the surrounding air - will increase.

Later still: The Greaser gets a cheesburger, fires, and malt *and* a date with Suzy the Cheerleader.... and you end up looking like Grandma's dog in Lampoon's Summer Vacation movie.

Disclaimer: *Never* tie yourself to the bumper of a car, especially a '57 Chevy driven by a hungry Greaser, with out without a skateboard ...

FWIW

For those "non-taker-offers", what's your take on this? This is the best example used in the thread yet on why the plane would take off.

He is wrong. The truck would not move it would sit there spinning its whells in the dirt. They only way it could move is to violate the speed of the treadmill matching the speed of the wheels.
 

Queasy

Moderator<br>Console Gaming
Aug 24, 2001
31,796
2
0
Originally posted by: knightc2
The plane struggles to fly, then pitches up before leveling off and becoming airborne. Then it suddenly losses altitude and crashes into this thread destroying all of the posts...

/thread

I seriously can't believe this thread is still going on when all I wanted to know if anyone else had heard that Mythbusters was going to be testing this.
 

sao123

Lifer
May 27, 2002
12,653
205
106
Originally posted by: smack Down
Originally posted by: Poulsonator
Originally posted by: ScottMac
OK, I read the whole thread. I'm amazed.

There was almost the right thing posted once ... the missing explanation:

You (non take-offers) are on a skateboard, which is located on a treadmill. You have a rope around your waist that is attached to a '57 Chevy's rear bumper.

Begin: the car is stationary. The treadmill starts up moving however fast you want it to go. The rope tightens and you remain stationary on the treadmill, relative to the surrounding air. The skateboard wheels match the speed of the treadmill belt.

Later: The greaser sitting at the wheel of the '57 Chevy (327, blower, pipes, upper/lower work) pops the clutch and zooms off to the burger stand. The rope will pull you off the front of the treadmill (trust me). Even if the treadmill speeds up to match the speed of the wheels on your skateboard, the rope (which would correspond to the prop of an airplane as a motivational force) is going to pull you forward and off the front of the treadmill. Your "airspeed" - how fast you are going relative to the surrounding air - will increase.

Later still: The Greaser gets a cheesburger, fires, and malt *and* a date with Suzy the Cheerleader.... and you end up looking like Grandma's dog in Lampoon's Summer Vacation movie.

Disclaimer: *Never* tie yourself to the bumper of a car, especially a '57 Chevy driven by a hungry Greaser, with out without a skateboard ...

FWIW

For those "non-taker-offers", what's your take on this? This is the best example used in the thread yet on why the plane would take off.

He is wrong. The truck would not move it would sit there spinning its whells in the dirt. They only way it could move is to violate the speed of the treadmill matching the speed of the wheels.

BWAHAHAHAHAHAHAHAHAHAHAHAHA

Biggest moron ever.
 

Rob9874

Diamond Member
Nov 7, 1999
3,314
1
81
Actually, the 2nd part of his statement is correct. The skateboard will move forward, but only by its wheels moving faster than the treadmill.
 

zinfamous

No Lifer
Jul 12, 2006
111,857
31,346
146
I'm sure that if mythbusters does tackle this problem, and reaches the type of conclusion that they tend to reach, another thread will begin on here debating the results of their conclusion and the very same string of arguments between idiots, imbeciles, and people with way too much time on their hands, will continue unabated.

:)
 

exdeath

Lifer
Jan 29, 2004
13,679
10
81
Originally posted by: zinfamous
I'm sure that if mythbusters does tackle this problem, and reaches the type of conclusion that they tend to reach, another thread will begin on here debating the results of their conclusion and the very same string of arguments between idiots, imbeciles, and people with way too much time on their hands, will continue unabated.

:)

All they have to do is borrow a factory or plant of some kind that has a large single run of conveyer and drop a running model airplane on it.

Turn on the belt and hit full throttle on the plane remote at the same time. Since it would be too complicated to precisely match the conveyer speed to the forward speed of the plane at the exact same time, they could predetermine a throttle position of the model airplane on still ground that results in a forward speed that matches the conveyer system selected; a speed that is sufficient for take off. Then with the throttle held to that position, drop the plane on an already moving conveyer belt.

I predict the plane would travel backwards along the conveyer for a brief instant, come to a rest, then proceed forward and take off, as the engine trust compensates for the initial momentum of the plane traveling on the conveyer belt.

If you wanted to exaggerate the fact that the plane can still take off regardless of the conveyer, you could even start the conveyer at full speed and start the plane at a deficit at idle. You would need enough space behind the plane for rearward travel until the thrust momentum builds up and compensates for the initial rearward inertia, and enough space in front to attain take off velocity shortly after.

It can be assumed then if the plane can recover from a Vconveyer > Vplane initial condition, than it would have even less of a problem with a Vconveyer = Vplane initial condition. The only difference is lack of the initial rearward movement and the time it takes to take off.
 

ShockwaveVT

Senior member
Dec 13, 2004
830
1
0
Originally posted by: sao123
Originally posted by: spidey07
As stated in the original description it is impossible for the plane to move forward.

No lift = no takeoff.


The original question makes no such claims... I have bolded it for you., along with the columnists comment directly refuting your claim...


The Pilot's Lounge #94: It's The Medium, Manfred Email this article |Print this article
There's a new aviation myth running around the Internet. It involves a conveyer-belt runway and misuse of aerodynamics and ... well, it's better if AVweb's Rick Durden explains it all himself in The Pilot's Lounge.
By Rick Durden, Columnist


The Pilot's Lounge
I heard the commotion as I started down the hall from the flight school to the Pilot's Lounge at the virtual airport. In the few moments it took to get to the door of the Lounge, individual voices became clear, split into two very vocal camps: The vehement "Yes it will!" calls being answered by an equally intense "No it won't!" I thought back to some of the stronger disagreements that had been aired here, such as the use of flaps on landing, but this one seemed a little louder and I wondered whether Old Hack and some of the bigger guys might have to separate combatants.
I stood off to the side and tried to get a handle on the conflict. Old Hack saw me and sidled over with a silly grin on his face. "These guys spend way too much time on the Internet," he said. "Someone has just come up with what looks like a 21st-century version of the old "downwind turn" foolishness and now the engineers and the soft-science folks are having at it."
...long unrelated part of the article omitted...


Conveyer-Belt Runway
What I learned from Old Hack was that an updated version of a question aimed at confusing folks over relative measurements of airplane motion and the medium in which it operates had shown up on the Internet, and it was causing the fracas in the Lounge.
The question that has been going around is not particularly artfully worded, and I think that has caused some of the disagreements, but I'll repeat it as it is shown: "On a day with absolutely calm wind, a plane is standing on a runway that can move (some sort of band conveyor). The plane moves in one direction, while the conveyor moves in the opposite direction. The conveyor has a control system that tracks the plane speed and tunes the speed of the conveyor to be exactly the same (but in the opposite direction). Can the airplane ever take off?"

My comment: Notice that the question does not state that the conveyor's movement keeps the airplane over the starting position relative to the ground, just that it moves in the direction opposite to any movement of the airplane.
Initially, about a third of the folks here said that the airplane could not ever takeoff, because the conveyor would overcome the speed of the airplane and it could never get any airspeed. The rest said the airplane would fly.
The "It won't fly, Rocky" group said that the conveyor would hold back the airplane. They asked us to imagine a person running on a treadmill. As he or she sped up, the treadmill would be programmed to speed up, just as the conveyor in the problem, and the person would remain over the same locus on the earth, while running as fast as possible.
The argument was that if the airplane started to move forward, the conveyor program was set up to move the conveyor at exactly that speed, in the opposite direction, thus, the airplane would never move relative to the ground, and, because the air was calm, it could never get any wind over its wings. One of the analogies presented was the person rowing at three mph upstream in a river on a calm day. However, the current was flowing downstream at three mph, so the resultant speed with reference to the stream bank and air was zero, and thus there was no wind on the rowboat.
I watched and listened to the disagreement for a while and was fascinated to see that the argument seemed to split between those who had some engineering or math background, all of whom said the airplane would takeoff and fly without any problem; and those with some other background, who visualized the airplane as having to push against the conveyor in order to gain speed. Because the conveyor equaled the airplane's push against the conveyor, the airplane stayed in one place over the ground and in the calm air could not get any airspeed and fly.
It was an interesting argument, but as things progressed, more rational heads prevailed, pointing out that the airplanes do not apply their thrust via their wheels, so the conveyor belt is irrelevant to whether the airplane will takeoff. One guy even got one of those rubber band powered wood and plastic airplane that sell for about a buck, put it on the treadmill someone foolishly donated to the Lounge years ago, thinking that pilots might actually exercise. He wound up the rubber band, set the treadmill to be level, and at its highest speed. Then he simultaneously set the airplane on the treadmill and let the prop start to turn. It took off without moving the slightest bit backwards.


Manfred In The 21st Century
OK, let's figure out why the airplane will fly.
We'll use Manfred again. Although we're bringing him forward into the 21st Century, we'll still let him use the 65 hp J-3. It doesn't really matter what airplane he flies, but he got used to the J-3 while he was demonstrating downwind turns and this one happens to have lifting rings on the top of the fuselage. It's also been modified with a starter so no one has to swing the prop.
Manfred's in the airplane. Old Hack has the Army-surplus crane fired up and he's picking up the J-3 and Manfred and carrying them over to Runway 27, which has been transformed into a 3,000-foot conveyor belt. It is a calm day. The conveyor drive is programmed so that if Manfred can start to move in the J-3, if he can generate any airspeed or groundspeed, the conveyor will move toward the east (remember Manfred and the J-3 are facing west) at exactly the speed of the air/groundspeed. Because the wind is calm, if Manfred can generate any indicated airspeed, he will also be generating precisely the same groundspeed. Groundspeed, of course being relative to the ground of the airport surrounding the conveyor belt runway. So, the speed of the conveyor belt eastbound will be the same as Manfred's indicated airspeed, westbound.
Manfred does his prestart checklist, holds the heel brakes, hits the starter and the little Continental up front clatters to life. Oil pressure comes up and stabilizes and Manfred tries to look busy because the eyes of the world are upon him, but all he can do is make sure the fuel is on and the altimeter and trim are set, then do a quick runup to check the mags and the carb heat. He moves the controls through their full travel and glares at the ailerons, doing his best to look heroic, then holds the stick aft in the slipstream to pin the tail and lets go of the brakes.


Baron of the Belt
So far the J-3 has not moved, nor has the conveyor. At idle power, there's not enough thrust to move the J-3 forward on a level surface, so Manfred starts to bring up the power, intending to take off. The propeller rpm increases and the prop shoves air aft, as it does on every takeoff, causing the airplane to move forward through the air, and as a consequence, forward with regard to the ground. Simultaneously the conveyor creaks to life, moving east, under the tires of the J-3. As the J-3 thrusts its way through the air, driven by its propeller, the airspeed indicator comes off the peg at about 10 mph. At that moment the conveyor is moving at 10 mph to the east and the tires are whirling around at 20 mph because the prop has pulled it to an airspeed, and groundspeed, of 10 mph, westbound. The airplane is moving relative to the still air and the ground at 10 mph, but with regard to the conveyor, which is going the other way at 10 mph, the relative speed is 20 mph.
Manfred relaxes a bit because the conveyor cannot stop him from moving forward. There is nothing on the airplane that pushes against the ground or the conveyor in order for it to accelerate; as Karen -- one of our techies here at the Lounge -- put it, the airplane freewheels. In technical terms, there is some bearing drag on the wheels, but it's under 40 pounds, and the engine has overcome that for years; plus the drag doesn't increase significantly as the wheel speed increases. Unless Manfred applies the brakes, the conveyor cannot affect the rate at which the airplane accelerates.
A few moments later, the roaring Continental, spinning that wooden Sensenich prop, has accelerated the J-3 and Manfred to 25 mph indicated airspeed. He and the airplane are cruising past the cheering spectators at 25 mph, while the conveyor has accelerated to 25 mph eastbound, yet it still has no way of stopping the airplane's movement through the air. The wheels are spinning at 50 mph, so the noise level is a little high, but otherwise, the J-3 is making a normal, calm-wind takeoff.
As the indicated airspeed passes 45 mph, groundspeed -- you know, relative to where all those spectators are standing beside the conveyor belt -- is also 45 mph. (At least that's what it says on Manfred's GPS. Being brought back to life seemed to create an insatiable desire for electronic stuff.) The conveyor is also at 45 mph, and the wheels are whizzing around at 90 -- the groundspeed plus the speed of the conveyor in the opposite direction.
Manfred breaks ground, climbs a few hundred feet, then makes a low pass to see if he can terrify the spectators because they are Americans, descendants of those who defeated his countrymen back in 1918.


It's All About Airspeed (Don't try this at home!)
While the speed of the conveyor belt in the opposite direction is superficially attractive in saying the airplane cannot accelerate, it truly is irrelevant to what is happening with the airplane, because the medium on which it is acting is the air. The only time it could be a problem is if the wheel speed got so high that the tires blew out.
Put another way, consider the problem with the J-3 mounted on a hovercraft body (yes, similar things were tried about 30 years ago). The hovercraft lifts the airplane a fraction of an inch above the conveyor belt, and so no matter how fast the conveyor spins, it cannot prevent the propeller -- acting on the air -- from accelerating the airplane to takeoff speed. It's the same with wheels rolling on the conveyor belt. Those wheels are not powered and thus do not push against the belt to accelerate the airplane. Were that the case, the vehicle could not reach an airspeed needed to fly, because then the conveyor, the medium acted upon by the propulsive force, would be able to negate the acceleration relative to the air and ground.
I'm reminded of the New York Times editorial when Robert Goddard's rocket experiments were first being publicized. The author of the editorial said that rockets can't work in space because they have nothing to push against. It was laughably wrong, ignoring one of Sir Isaac's laws of physics that for every action there is an equal and opposite reaction. Here the propeller is pushing against the air, as it does every time an airplane takes off. How fast the airplane is moving over the surface on which its wheels rest is irrelevant; the medium is the magic. On a normal takeoff -- no conveyor involved -- if there is a 20 mph headwind, Manfred and the J-3 will lift off at 45 mph indicated airspeed; but relative to the ground, it is only 25 mph. Should the wind increase to 45 mph and if Manfred can get to the runway, he can take off without rolling an inch. His airspeed is 45 and groundspeed is zero. It is not necessary to have any groundspeed to fly, just airspeed. Conversely, if Manfred has a lot of runway and no
thing to hit, and takes off downwind in a 25 mph tailwind, the propeller will have to accelerate the airplane to a zero airspeed, which will be a 25 mph groundspeed, and then on to a 45 mph airspeed, which will have him humming across the ground at 70 mph. The speed over the ground, or a conveyor belt, when an airplane takes off is irrelevant; all that matters is its speed through the air, and unless the pilot sets the brakes, a moving conveyor belt -- under the freely turning wheels -- cannot stop the process of acceleration.
Things eventually calmed down as the number of "it won't fly" folks dwindled as they began to understand that the airplane would take off. Old Hack looked at me and suggested we depart as the few holdouts showed no sign of changing their position. So, we headed out into the night to watch the guys take the conveyor out and reinstall the runway.

See you next month.

 

smack Down

Diamond Member
Sep 10, 2005
4,507
0
0
Originally posted by: exdeath
Originally posted by: zinfamous
I'm sure that if mythbusters does tackle this problem, and reaches the type of conclusion that they tend to reach, another thread will begin on here debating the results of their conclusion and the very same string of arguments between idiots, imbeciles, and people with way too much time on their hands, will continue unabated.

:)

All they have to do is borrow a factory or plant of some kind that has a large single run of conveyer and drop a running model airplane on it.

Turn on the belt and hit full throttle on the plane remote at the same time. Since it would be too complicated to precisely match the conveyer speed to the forward speed of the plane at the exact same time, they could predetermine a throttle position of the model airplane on still ground that results in a forward speed that matches the conveyer system selected; a speed that is sufficient for take off. Then with the throttle held to that position, drop the plane on an already moving conveyer belt.

I predict the plane would travel backwards along the conveyer for a brief instant, come to a rest, then proceed forward and take off, as the engine trust compensates for the initial momentum of the plane traveling on the conveyer belt.

If you wanted to exaggerate the fact that the plane can still take off regardless of the conveyer, you could even start the conveyer at full speed and start the plane at a deficit at idle. You would need enough space behind the plane for rearward travel until the thrust momentum builds up and compensates for the initial rearward inertia, and enough space in front to attain take off velocity shortly after.

It can be assumed then if the plane can recover from a Vconveyer > Vplane initial condition, than it would have even less of a problem with a Vconveyer = Vplane initial condition. The only difference is lack of the initial rearward movement and the time it takes to take off.

You can't do any experiment and have valid results. The question is therorical.
 

randay

Lifer
May 30, 2006
11,018
216
106
Originally posted by: smack Down
You can't do any experiment and have valid results. The question is therorical.

One could easily create this experiment on small scale. The question is not "therorical", whatever that means.
 

spidey07

No Lifer
Aug 4, 2000
65,469
5
76
Originally posted by: randay
Originally posted by: smack Down
You can't do any experiment and have valid results. The question is therorical.

One could easily create this experiment on small scale. The question is not "therorical", whatever that means.

It absolutely is theoretical. As has already been explained. Such a device does not exist in the real world as it's possible of infinite acceleration as outlined by the original question.
 

AbsolutDealage

Platinum Member
Dec 20, 2002
2,675
0
0
Originally posted by: smack Down
You can't do any experiment and have valid results. The question is therorical.

Even if you convince yourself that you can't test the plane, you could certainly test this:

Originally posted by: smack Down
He is wrong. The truck would not move it would sit there spinning its whells in the dirt. They only way it could move is to violate the speed of the treadmill matching the speed of the wheels.

I mean, come on. Do you really believe this? It's the same as the whole treadmill/matchbox car argument from before. If you had your finger on a matchbox car that was on a treadmill, do you really think that the treadmill could stop you from pushing the car forward?

Well, whatever. You couldn't possibly believe that, so you are just a troll at this point.
 

smack Down

Diamond Member
Sep 10, 2005
4,507
0
0
Originally posted by: AbsolutDealage
Originally posted by: smack Down
You can't do any experiment and have valid results. The question is therorical.

Even if you convince yourself that you can't test the plane, you could certainly test this:

Originally posted by: smack Down
He is wrong. The truck would not move it would sit there spinning its whells in the dirt. They only way it could move is to violate the speed of the treadmill matching the speed of the wheels.

I mean, come on. Do you really believe this? It's the same as the whole treadmill/matchbox car argument from before. If you had your finger on a matchbox car that was on a treadmill, do you really think that the treadmill could stop you from pushing the car forward?

Well, whatever. You couldn't possibly believe that, so you are just a troll at this point.

A real treadmill would be unable to stop the truck but that doesn't matter.

We are not talking about a real treadmil.
 

spidey07

No Lifer
Aug 4, 2000
65,469
5
76
Originally posted by: smack Down
A real treadmill would be unable to stop the truck but that doesn't matter.

We are not talking about a real treadmil.

You are one of the few people who are smart enough to actually get it. Bravo.
:thumbsup:
 

Fatalist

Member
Nov 25, 2001
26
0
0
The key to this problem is that the force of friction has an upper bound. Ff = u N
u : coefficient of friction
N : normal force
Ff : MAXIMUM force of friction

What is the normal force in this scenario? It is perpendicular to the direction of motion: the weight of the aircraft. Note that the speed of the treadmill does not matter!
The treadmill can exert a maximum of Ff on the wheels. It can exert less, but never more than Ff. Even if the treadmill is moving at infinite speed it is only exerting Ff on the wheels.
All that is necessary is the thrust of the plane's engines exceed Ff, which is a finite quantity.
 

Cerpin Taxt

Lifer
Feb 23, 2005
11,940
542
126
Originally posted by: smack Down
Originally posted by: Poulsonator
Originally posted by: ScottMac
OK, I read the whole thread. I'm amazed.

There was almost the right thing posted once ... the missing explanation:

You (non take-offers) are on a skateboard, which is located on a treadmill. You have a rope around your waist that is attached to a '57 Chevy's rear bumper.

Begin: the car is stationary. The treadmill starts up moving however fast you want it to go. The rope tightens and you remain stationary on the treadmill, relative to the surrounding air. The skateboard wheels match the speed of the treadmill belt.

Later: The greaser sitting at the wheel of the '57 Chevy (327, blower, pipes, upper/lower work) pops the clutch and zooms off to the burger stand. The rope will pull you off the front of the treadmill (trust me). Even if the treadmill speeds up to match the speed of the wheels on your skateboard, the rope (which would correspond to the prop of an airplane as a motivational force) is going to pull you forward and off the front of the treadmill. Your "airspeed" - how fast you are going relative to the surrounding air - will increase.

Later still: The Greaser gets a cheesburger, fires, and malt *and* a date with Suzy the Cheerleader.... and you end up looking like Grandma's dog in Lampoon's Summer Vacation movie.

Disclaimer: *Never* tie yourself to the bumper of a car, especially a '57 Chevy driven by a hungry Greaser, with out without a skateboard ...

FWIW

For those "non-taker-offers", what's your take on this? This is the best example used in the thread yet on why the plane would take off.

He is wrong. The truck would not move it would sit there spinning its whells in the dirt. They only way it could move is to violate the speed of the treadmill matching the speed of the wheels.

It has never been about the speed of the wheels. It has always been about the speed of the plane. You've been told this several times already, yet you persist under your obviously mistaken interpretation.

At this point, there is nothing left to conclude but that you are doing so deliberately, meaning you are trolling. What on earth motivates you to do such a thing? Mommy and Daddy didn't give you enough attention?
 

randay

Lifer
May 30, 2006
11,018
216
106
Originally posted by: spidey07
Originally posted by: randay
Originally posted by: smack Down
You can't do any experiment and have valid results. The question is therorical.

One could easily create this experiment on small scale. The question is not "therorical", whatever that means.

It absolutely is theoretical. As has already been explained. Such a device does not exist in the real world as it's possible of infinite acceleration as outlined by the original question.

you seem geniunely not a troll. so i will try and explain it to you. there are two possible interpretations and that is the problem here.

1. the treadmill matches the speed of the airplane relative to the ground/atmosphere.
2. the treadmill matches the speed of the airplane relative to its own(the treadmill's) surface.

now case 1 is the most obvious and logical interpretation. since by your own admission case 2 is impossible. in case 1 you do not need infinite acceleration, the treadmill only needs to match the acceleration of the airplane, which is not infinite. In case 2, acceleration doesnt matter at all, since the treadmill can never(its impossible) match the airplanes speed relative to itself, the only time it does match is at zero.

 

smack Down

Diamond Member
Sep 10, 2005
4,507
0
0
Originally posted by: randay
Originally posted by: spidey07
Originally posted by: randay
Originally posted by: smack Down
You can't do any experiment and have valid results. The question is therorical.

One could easily create this experiment on small scale. The question is not "therorical", whatever that means.

It absolutely is theoretical. As has already been explained. Such a device does not exist in the real world as it's possible of infinite acceleration as outlined by the original question.

you seem geniunely not a troll. so i will try and explain it to you. there are two possible interpretations and that is the problem here.

1. the treadmill matches the speed of the airplane relative to the ground/atmosphere.
2. the treadmill matches the speed of the airplane relative to its own(the treadmill's) surface.

now case 1 is the most obvious and logical interpretation. since by your own admission case 2 is impossible. in case 1 you do not need infinite acceleration, the treadmill only needs to match the acceleration of the airplane, which is not infinite. In case 2, acceleration doesnt matter at all, since the treadmill can never(its impossible) match the airplanes speed relative to itself, the only time it does match is at zero.

Case 1 is not the most obvious or logical interpretation. When people think about treadmills they consider the speed of the object on the treadmill with reference to the treadmill surface. Go down to a gym and ask 10 people how fast are they running and 99% of them will give a speed that references the treadmill surface and not ground. So in fact case 2 is the most obvious interpolation of the question.

Oh in case you can't figure it out wheel speed is the same as plane speed with reference to the treadmill.
 

async

Member
Jun 7, 2002
37
0
0
If the treadmill is free running so that it matches the velocity of the plane relative to the ground, then the plane will take off for all the reasons already mentioned with the wheels spinning at twice the usual angular velocity.

If the treadmill is programmed to match the rotational speed of the wheels at the circumference, then the wheels are going to speed up exponentially, the bearings will eventually seize (or the tyres will explode) and the landing gear will get ripped off causing massive structural damage to the plane.

In the real world you would expect some form of explosion.
In a test environment with a model plane you'll get a confused gym patron with a toy plane stuck up his ass.

John
 

Rogodin2

Banned
Jul 2, 2003
3,219
0
0
So you guys (Spidey and Smackdown) are proposing that the argument is theorical because the only way in which the treadmill could compensate for thrust is if it was a 'special theoritcal'? I think that the only theoretical part of the question is the friction and the speed matching capability of the treadmill.

Rogo
 

T9D

Diamond Member
Dec 1, 2001
5,320
6
0
Here is what will happen:


The plane needs air moving over it's wings. Without that wind the plane can NOT use it's flaps to angle them up to cause pressure to get the plane into the air.

YES thrust can move it forward even when not on a treadmill but it HAS to have that wind to get it in the air. If it does not have this the plane will just continue to move forward and not ever get lift and fly. (We are of course assuming that the engines are pointed streight ahead like a normal plane)

It will put it's flaps up and NOTHING will happen. It will just sit there. Like a plane with no wings. So if the flaps are useless HOW can the plane take off? It can't. A plane with no flaps or useless flaps cant take off. Thats how a plane works.

But it can cause forward FORCE. So if the treadmill/conveyor belt matches it's force it will forever stay on the ground. Yes there is thrust to give it forward push but it will be matched by the treadmill so it will stay in one place ONLY causeing foward force but not taking off. It can not go any faster than the treadmill because if whatever force the plane uses to be able to make it push ahead even one inch on the treadmill the treadmill will compensate and speed up to a point that is equal to what that plane needed to move ahead. Using only what is on it's side....gravity and friction (the treadmills side). So it will never move that inch or any at all foward.

Now...however the plane is still causeing air to be moved. through it's engines. At some point and some power of thrust the plane is going to be sucking so much air through that area that eventually it's going to cause the entire atmosphere to start moving and passing over it's wings also. At this point it will start to build up wind speed over it's wings. This will take an amazing amount of thrust and way above it's normal speed. At some point it will be fast enough to make the flaps usefull. At that second those flaps can give it some lift the plane will pull up and shoot foward with insane speed and rocket off that treadmill now that there is no more force pushing against it's wheels and causeing friction on the wheels, bearings etc (since it is no longer in contact with the treadmill at all). And it will be flying. Now it will be airborn and using air pressure and wind speed to keep it up.

Now if you have a prop plane this will happen much faster since the prop is in front of the flaps and pushing wind over the wings. Making the flaps usefull much sooner. But once it gets off the ground it will have to have enough force to propell it forward fast enough to catch enough air pressure to keep it up after it leaves the threadmill.




*some side notes*: A plane in space will NOT be able to take off (assuming it has air suppied to the jet fuel to ignite it). It would ONLY be able to move FORWARD. Flaps would be useless with no air in space unless postioned behind the engine thrust or the engine actually moved itself. This is why the plane would just sit there on a treadmill and not get lift at first. Thrust can push it foward it can't steer it.

*2nd note*: Put the plane on the treadmill. Start the treadmill.... what happens? It goes backward. Apply thust to keep it in one place. Then make the treadmill move faster.... the plane will now have to apply even more thrust to keep it from falling behind. So it does take power and thrust to compensate for the friction and gravity and whatnot. And that increases as the threadmill moves faster. I know it sounded bizzare at first but that guy that said the truck would just spin tires if pulling someone on a treadmill is correct. If that treadmill is moving 1000 MPH (random speed I chose) its going to be causeing an insane amount of pull back on that truck. The point in mentioning this is basicly that the faster the treadmill goes the more force back it will cause and if it can go to any speed it can match any force moving forward.

So in a way both sides are correct up to a point :)
 

Number1

Diamond Member
Feb 24, 2006
7,881
549
126
Originally posted by: tk109
Here is what will happen:


The plane needs air moving over it's wings. Without that wind the plane can NOT use it's flaps to angle them up to cause pressure to get the plane into the air.

YES thrust can move it forward even when not on a treadmill but it HAS to have that wind to get it in the air. If it does not have this the plane will just continue to move forward and not ever get lift and fly. (We are of course assuming that the engines are pointed streight ahead like a normal plane)

It will put it's flaps up and NOTHING will happen. It will just sit there. Like a plane with no wings. So if the flaps are useless HOW can the plane take off? It can't. A plane with no flaps or useless flaps cant take off. Thats how a plane works.

But it can cause forward FORCE. So if the treadmill/conveyor belt matches it's force it will forever stay on the ground. Yes there is thrust to give it forward push but it will be matched by the treadmill so it will stay in one place ONLY causeing foward force but not taking off. It can not go any faster than the treadmill because if whatever force the plane uses to be able to make it push ahead even one inch on the treadmill the treadmill will compensate and speed up to a point that is equal to what that plane needed to move ahead. Using only what is on it's side....gravity and friction (the treadmills side). So it will never move that inch or any at all foward.

Now...however the plane is still causeing air to be moved. through it's engines. At some point and some power of thrust the plane is going to be sucking so much air through that area that eventually it's going to cause the entire atmosphere to start moving and passing over it's wings also. At this point it will start to build up wind speed over it's wings. This will take an amazing amount of thrust and way above it's normal speed. At some point it will be fast enough to make the flaps usefull. At that second those flaps can give it some lift the plane will pull up and shoot foward with insane speed and rocket off that treadmill now that there is no more force pushing against it's wheels and causeing friction on the wheels, bearings etc (since it is no longer in contact with the treadmill at all). And it will be flying. Now it will be airborn and using air pressure and wind speed to keep it up.

Now if you have a prop plane this will happen much faster since the prop is in front of the flaps and pushing wind over the wings. Making the flaps usefull much sooner. But once it gets off the ground it will have to have enough force to propell it forward fast enough to catch enough air pressure to keep it up after it leaves the threadmill.




*some side notes*: A plane in space will NOT be able to take off (assuming it has air suppied to the jet fuel to ignite it). It would ONLY be able to move FORWARD. Flaps would be useless with no air in space unless postioned behind the engine thrust or the engine actually moved itself. This is why the plane would just sit there on a treadmill and not get lift at first. Thrust can push it foward it can't steer it.

*2nd note*: Put the plane on the treadmill. Start the treadmill.... what happens? It goes backward. Apply thust to keep it in one place. Then make the treadmill move faster.... the plane will now have to apply even more thrust to keep it from falling behind. So it does take power and thrust to compensate for the friction and gravity and whatnot. And that increases as the threadmill moves faster. I know it sounded bizzare at first but that guy that said the truck would just spin tires if pulling someone on a treadmill is correct. If that treadmill is moving 1000 MPH (random speed I chose) its going to be causeing an insane amount of pull back on that truck. The point in mentioning this is basicly that the faster the treadmill goes the more force back it will cause and if it can go to any speed it can match any force moving forward.

So in a way both sides are correct up to a point :)

What where you smoking?
 

mugs

Lifer
Apr 29, 2003
48,920
46
91
Originally posted by: spidey07
Originally posted by: smack Down
A real treadmill would be unable to stop the truck but that doesn't matter.

We are not talking about a real treadmil.

You are one of the few people who are smart enough to actually get it. Bravo.
:thumbsup:

This is the kind of response you get from a troll having a temper tantrum.

You seem to be intent on discussing the version of the problem that defies the laws of physics - and because the situation described in the problem cannot exist you take that to mean that it can't take off. On the contrary - how can you say if the plane would or would not take off if the situation it's supposed to take off in can't exist in the first place?

Even if you insist on using the poorly worded version of the problem, the answer is yes, the plane can still take off. A plane does not need to move relative to the ground in order to take off. You know how a plane has an airspeed and a ground speed? And they're not always the same? The airspeed is the one that matters, because that determines how much lift the wings generate. It doesn't matter what your groundspeed is, if you have a high enough airspeed the plane will leave the ground.

In other words - strong gust of wind.

But an intelligent person would use the version of the question that does not describe an impossible scenario. (That is, the version of the question where the treadmill matches the plane's speed relative to the ground, not the rotational speed of the wheels)