More Algebra questions

[Zap Brannigan]

I need postive exponents for this solution that we already did, -24x^-9/20 y^1/2

If we went (1/24x^9/20 ) y^1/2 would that make sense?

 

[randumb]

misread OP

 

[Zap Brannigan]

Or check this out, would y^1/2 over 24x^9/20 make more sense?

 

[Zap Brannigan]

Originally posted by: randumb
misread OP

No prob! Everyone is being a great help!

 

[dighn]

Originally posted by: Zap Brannigan
Or check this out, would y^1/2 over 24x^9/20 make more sense?

however did you get 9/20? check out mwtgg's answer. that's exactly what you want. I didn't realize you needed positive exponents

 

[Zap Brannigan]

Here is the next one that needs to be simplified with positve exponents,

(16a^5 b^-2 / a^-1 b^-6) 1/2

 

[Zap Brannigan]

Originally posted by: dighn

Originally posted by: Zap Brannigan
Or check this out, would y^1/2 over 24x^9/20 make more sense?

however did you get 9/20? check out mwtgg's answer. that's exactly what you want. I didn't realize you needed positive exponents

Crap I must have mistyped. I needed postive exponent from a solutiuon that I typed in another thread before decding to make one thread for multiple problems.

I needed a postive exponent from a solution in another thread that came out to be -24x^-9/20 y^1/2

My bad!

 

[Zap Brannigan]

Originally posted by: Zap Brannigan
Here is the next one that needs to be simplified with positve exponents,

(16a^5 b^-2 / a^-1 b^-6) 1/2

For this one I got,

-4a^5/2 b/ a^-1/2 b^-3

Now we need to have this a solution wiht positive exponents...

 

[hypn0tik]

How old are you OP?

 

[Zap Brannigan]

How does a^2 b^2 /4 look?

 

[Zap Brannigan]

Originally posted by: hypn0tik
How old are you OP?

I'm 28. This is for a college class, and yes I'm rusty as all get out lol.

 

[hypn0tik]

Originally posted by: Zap Brannigan
How does a^2 b^2 /4 look?

Looks wrong to me.

Simplify the stuff inside the brackets first.

You should get:

(16a^6 b^4)^(1/2) = 4a^3 b^2

 

[Zap Brannigan]

It's 16a^5 not 6th.

Oh wait I think I see what you did

 

[hypn0tik]

Originally posted by: Zap Brannigan
It's 16a^5 not 6th.

Right, but you have an a^-1 in the denominator. If you simply 16a^5/a^-1, you get 16a^6

 

[Zap Brannigan]

Sweet! Math is so beautiful when done right.

 

[hypn0tik]

Originally posted by: Zap Brannigan
Sweet! Math is so beautiful when done right.

Hehe. Yep.

If you need anything else, feel free to PM me.

 

[Zap Brannigan]

OK, now to evaluate (-64)^2/3

 

[hypn0tik]

Originally posted by: Zap Brannigan
OK, now to evaluate (-64)^2/3

Go for it. Let me know what you get.

 

[Zap Brannigan]

I got 16

 

[Zap Brannigan]

Does that look right to you?

 

[hypn0tik]

Originally posted by: Zap Brannigan
I got 16

Yep.

 

[Zap Brannigan]

Cool! Now to evaluate the cubed root of -125.

How would I type that equation in numbers on here?

 

[Zap Brannigan]

The answer I got was -5^3

 

[hypn0tik]

Originally posted by: Zap Brannigan
Cool! Now to evaluate the cubed root of -125.

How would I type that equation in numbers on here?

Cube root is the equivalent of taking the number to the exponent of 1/3

So, cube root of -125 --> (-125)^1/3

 

[Zap Brannigan]

Ah, very cool!