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'Mathlete' breaks calculation record - 13th root of a random 200 digit number

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Originally posted by: mobobuff
Originally posted by Farang
...473,838,49,584,738...

Hmmmmm?

I knew someone was going to point that out. I started fixing it then realized it took too long and said screw it, thinking there was a small chance I'd get away with it.
 
I think the human brain is capable of so much more, but few people can tap into that level of computational power consciously.
 
Calculating the 13th root of 100-digit numbers has been a yardstick for the world's leading "mathletes" since a Herbert B. de Grote achieved the feat in 23 minutes in 1970. Mr Lemaire first claimed that record in 2002 but gave up the challenge three years ago after completing it in 3.6 seconds.

:shocked::shocked::shocked::shocked::shocked:

By the way, is "maths" a correct term for multiple forms of math? I always thought it was like "deer."
 
Originally posted by: RapidSnail
Calculating the 13th root of 100-digit numbers has been a yardstick for the world's leading "mathletes" since a Herbert B. de Grote achieved the feat in 23 minutes in 1970. Mr Lemaire first claimed that record in 2002 but gave up the challenge three years ago after completing it in 3.6 seconds.

:shocked::shocked::shocked::shocked::shocked:

By the way, is "maths" a correct term for multiple forms of math? I always thought it was like "deer."

In "British" English they generally use maths..since it's a shortened version of mathematics, which is never "mathematic".
 
It took me three seconds to do the same. I wrote a program in three seconds that generated a random 200-digit number and calculated the 13th root of it. The CPU time required was on the order of microseconds. BAM!
 
Originally posted by: Imp
Woohoo... once the "machine" goes down, we'll flock to him to find our tenth root for...something?

Yeah, or we could use methods that "the machine" is programmed to use 😛
 
Originally posted by: Syringer
Originally posted by: RapidSnail
Calculating the 13th root of 100-digit numbers has been a yardstick for the world's leading "mathletes" since a Herbert B. de Grote achieved the feat in 23 minutes in 1970. Mr Lemaire first claimed that record in 2002 but gave up the challenge three years ago after completing it in 3.6 seconds.

:shocked::shocked::shocked::shocked::shocked:

By the way, is "maths" a correct term for multiple forms of math? I always thought it was like "deer."

In "British" English they generally use maths..since it's a shortened version of mathematics, which is never "mathematic".

Makes sense.

Originally posted by: sdifox
Originally posted by: EKKC
he's abnormal

Abby Normal is his proper name.

:thumbsup::laugh:
 
Originally posted by: Born2bwire
Originally posted by: steppinthrax
I you read the article it mentions "Alexis Lemaire trains for around four hours per day, practising calculations and memorising thousands of tables of numbers" There are a lot of patterns that are related to each other when doing calculations. A good example is multiplying by 9. In grade school many were taught when doing multiplication facts when multiplying by 9 the first digit in the answer is always one less than the number other than 9.

Example

9 x 2 = [1]8
9 x 3 = [2]7
9 x 4 = [3]6.

This is a very simple relationship but there are much much more complicated relationships when making complicated calculations. So in other words if you memorize most if not all of those relationships and find new patterns out yourself you can effectivley work out large numbers. So I highly doubt he calculated this from scratch. He looked at the digits and could deduct relationships of what the root could be......

Another one is calculating the square of numbers around 50. You take 2500, subtract a 100 times the difference between 50 and the number. Then you just add a correction that is equal to the square of the difference.

45: 2500-500+25 = 2025
57: 2500+700+49 = 3249

And so on. It's an easy relationship that you can derive from taking the square of (50-a) and stuff like that. It comes out: (50-a)^2 = 50^2-100*a+a^2 and 50 just happens to be an easy number to remember.

There's a neat trick for finding the square of numbers that end in 5.

E.g. 25*25

The last two digits are always 25. The rest of the digits can be found by:

25*25 = 625 (2*2 + 2 = 6)

115*115 = 11*11 + 11 --> 13225
 
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