Math Question

AgaBoogaBoo

Lifer
Feb 16, 2003
26,108
5
81
sin(-X) = -sinX

That works for sin, csc, tan, and cot

Why doesn't it work for cos and sec?
 

dataxpress

Banned
Jan 7, 2005
257
0
0
not sure why it doesn't work, it just doesn't.
Probably involves how cosine relates to the X-Axis, and Sec is related to Cos (Sec = 1/Cos)
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
sin is an odd function and cos is an even function, observe the symmetry about the y-axis. Alternately, you can look at the MacLaurin expansion terms to understand why cos is even and sin is odd.
 

Rayden

Senior member
Jun 25, 2001
790
1
0
If you look at the graph of even and odd functions you will see.

Cos is symmetric with respect to the y axis. cos(x) and cos(-1) give the same height to the graph. Sin is odd, that is it is mirrored vertically and horizontally. sin(-x) will give you the same as -sin(x). Look at the graphs.
 

jman19

Lifer
Nov 3, 2000
11,225
664
126
Originally posted by: AgaBoogaBoo
sin(-X) = -sinX

That works for sin, csc, tan, and cot

Why doesn't it work for cos and sec?

Easy explaination: look at the graphs of the above mentioned functions.
More difficult: look at the terms of the expansions of both sin and cos...
 

GiLtY

Golden Member
Sep 10, 2000
1,487
1
0
Easiest way to see it is using the standard circle. Cos(theta) is the x coordinate, any theta you have, Cos(-theta) will give you the same x.

--GiLtY