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Math Question

not sure why it doesn't work, it just doesn't.
Probably involves how cosine relates to the X-Axis, and Sec is related to Cos (Sec = 1/Cos)
 
sin is an odd function and cos is an even function, observe the symmetry about the y-axis. Alternately, you can look at the MacLaurin expansion terms to understand why cos is even and sin is odd.
 
If you look at the graph of even and odd functions you will see.

Cos is symmetric with respect to the y axis. cos(x) and cos(-1) give the same height to the graph. Sin is odd, that is it is mirrored vertically and horizontally. sin(-x) will give you the same as -sin(x). Look at the graphs.
 
Originally posted by: AgaBoogaBoo
sin(-X) = -sinX

That works for sin, csc, tan, and cot

Why doesn't it work for cos and sec?

Easy explaination: look at the graphs of the above mentioned functions.
More difficult: look at the terms of the expansions of both sin and cos...
 
Easiest way to see it is using the standard circle. Cos(theta) is the x coordinate, any theta you have, Cos(-theta) will give you the same x.

--GiLtY
 
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