Math problem

jeffeh

Banned
Dec 8, 2004
304
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0
x-3 x^2
---- * ----
3x x^2-9

ok so this is the problem.... When i worked it out I got 3(x+3)(x+0) is this correct?
Thanks, and if you anyone excels in math and wouldn't mind helping me out with some other question it would greatly appreciated.

 

Kyteland

Diamond Member
Dec 30, 2002
5,747
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Assuming that the above problem is actually ((x-3) / (3x)) * ((x^2) / (x^2-9)) then nope, the correct answer is not 3x(x+3).
 

chuckywang

Lifer
Jan 12, 2004
20,133
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I'm not sure I can read your expression since it's poorly formatted, however if it is what I think it is, the answer you get is: x/(3*(x+3))
 

Kyteland

Diamond Member
Dec 30, 2002
5,747
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Originally posted by: jeffeh
any idea what the answer would be?
The point of getting help on your homework isn't to be supplied with the anwer, but to learn how to do it on your own. Please show us what you did to get your previous answer and we'll offer you advice on what you did wrong and how to go about solving it correctly.
 

vrbaba

Diamond Member
Jul 17, 2003
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Originally posted by: chuckywang
I'm not sure I can read your expression since it's poorly formatted, however if it is what I think it is, the answer you get is: x/(3*(x+3))

i cant read it either....the answer i got is
((x^2)-3x)/((3x^2)-27)
 
Oct 20, 2005
10,978
44
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Originally posted by: jeffeh
x-3 x^2
---- * ----
3x x^2-9

ok so this is the problem.... When i worked it out I got 3(x+3)(x+0) is this correct?
Thanks, and if you anyone excels in math and wouldn't mind helping me out with some other question it would greatly appreciated.

If you actually open a quote window, you can see the problem a lot easier.

But jeffeh...this is insanely easy math. How can you have this much trouble?
 

stan394

Platinum Member
Jul 8, 2005
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Originally posted by: chuckywang
I'm not sure I can read your expression since it's poorly formatted, however if it is what I think it is, the answer you get is: x/(3*(x+3))


oOoO chuckywang is back :beer:
 

Kyteland

Diamond Member
Dec 30, 2002
5,747
1
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Originally posted by: Schfifty Five
But jeffeh...this is insanely easy math. How can you have this much trouble?
Everyone has to start somewhere. That's the point of learning. I remember struggling with math that I can do in my sleep now. There's no reason to put him down over it.
 

kevinthenerd

Platinum Member
Jun 27, 2002
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Originally posted by: Kyteland
Originally posted by: Schfifty Five
But jeffeh...this is insanely easy math. How can you have this much trouble?
Everyone has to start somewhere. That's the point of learning. I remember struggling with math that I can do in my sleep now. There's no reason to put him down over it.

so true. I remember when I didn't know what a derivative is.
 

kevinthenerd

Platinum Member
Jun 27, 2002
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(x^2-9) on the bottom right factors by the difference of squares: (x-3)*(x+3)

Then the (x-3) cancels from the top left, leaving 1 up there and just the (x+3) on the bottom right.

x^2 and 3x cancel, leaving x on the top right and 3 on the bottom left


(open this in a quote window to see it easily)

1 x
--- * -------
3 (x+3)


giving you

x
-------
3(x+3)