Math help, please.

[Nocturnal]

Basic algebra graphing stuff.

A linear equation in two variables is an equation that can be put in the form ax + by = c.

Where a, b, and c are real numbers.

y = 5x + 3 = when you convert it, -5x + y = 3 <------- HOW DID THE BOOK GET FROM Y = 5X + 3 TO -5X + Y =3.

This is working with the ax + by = c equation.

 

[agnitrate]

[edit] Yup. -5x from both sides and it evens out. [/edit]


-silver

 

[minendo]

Subtract 5x from both sides.

 

[Nocturnal]

Originally posted by: agnitrate
For the love of God tell me you are joking.

-silver

I'm not joking.

 

[Jzero]

subtract 5x from both sides of the equation IT'S MATHEMAGICAL!!!!

 

[isekii]

well they just put it back into the Ax+By= C

C being the constant ( y intercept )
A being the Slope
don't remember what the B value is

 

[Nocturnal]

Originally posted by: minendo
Subtract 5x from both sides.

Thanks, this is all that was needed to be said.

Thanks again.

I didn't know you could do that in order to make it like that. I thought it was some complicated process. If I knew you could do that like a regular algebra problem I would've done it, duh!

 

[thirtythree]

Hmm ..

 

[dighn]

:Q

its ok though. different ppl are good at different things. otherwise the world would be a boring place

 

[Nocturnal]

I never said I was a math genuis, hence the reason I'm asking here. Thank God for ATOT.

 

[src]

Can Someone PLEASE help me with this Laplace transform?

(Didn't want to start my own thread)

y" - y' -2y = -8cost -2sint
y(pi/2)=1
y'(pi/2)=0

I know you need w(t)=y(t+pi/2)
but then what is the transform of

-8cos(t+pi/2) - 2sin(t+pi/2) ?

Thank you

 

[DanFungus]

Originally posted by: src
Can Someone PLEASE help me with this Laplace transform?

(Didn't want to start my own thread)

y" - y' -2y = -8cost -2sint
y(pi/2)=1
y'(pi/2)=0

I know you need w(t)=y(t+pi/2)
but then what is the transform of

-8cos(t+pi/2) - 2sin(t+pi/2) ?

Thank you

*crickets*

sorry, haven't taken that yet...whatever that could be categorized under