Originally posted by: Idontcare
Originally posted by: IntelUser2000
Originally posted by: MODEL3
I just wanted to point, what kind of increase to the die size brings, the integration of the memory controller and the pci-express in addition to the Nehalem architecture in relation with the Core 2 architecture (which is natural...)
Actually, the 32nm Clarkdale CPU die alone (not including the seperate IGP die) should be just a little bit bigger (in size, mm2) than a 32nm 8200 (with 4MB native cache) die.
The major cost increase using a 32nm Core 2 Quad isn't die size, but its about making a whole new die and product out using a shrink.
Anyway if they do a perfect 50% shrink it'll end up to be little less than 100mm2 which makes it 20% larger than supposed die for Clarkdale(80-85mm2).
That was my thinking too, but I assumed I must be misreading model3's post because it (his post, not yours) really doesn't make sense so I didn't post anything on it.
It reads like he is saying a 32nm yorkfield shrink product would be smaller die than a 2C/4T 32nm westmere, which I don't see how anyone could convince themselves of this considering that a 45nm nehalem is about the same size as a 45nm yorkfield, so if just shrink the yorkfield but you shrink and cut in-half the core count of nehalem it stands to reason the cut-down nehalem is likely to be the smaller die.
So I'm thinking I am just misinterpreting Model3's post and he didn't mean to communicate this as his point.
edit: added clarifier as to what wasn't making sense to me in the first sentence.
No IDC, with the info we had at the time of writing my post it makes perfect sense. (see below...)
In my original post i said:
"I just wanted to point, what kind of increase to the die size brings, the integration of the memory controller and the pci-express in addition to the Nehalem architecture in relation with the Core 2 architecture."
I didn't see
anyone to reply to me that the memory controller and the pci-express will
not be on the CPU die this time.
So with the above perspective it makes sense. (actually If you only compare a 45nm Nehalem like Lynnfield and (
like you say) cut in-half the core count of nehalem it makes
absolute sense)
In my original post I said 32nm 8200 with 4MB
native cache
O.K. below are the calculations:
45nm 9400 6MB cache: die size 82mm2*2=164mm2
45nm 9450 12MB cache: die size 107mm2*2=214mm2
6MB cache die size=214mm2 - 164mm2 = 50mm2
2MB cache die size=50mm2/3 = 16,7mm2
die size of 45nm 8200 (
with 4MB native cache) =
147,3mm2
45nm Nehalem i5 750 8MB cache=296mm2
296mm2 / 2=
148mm2
So same (
not less) 45nm die size.
The thing is that the i5 750 die size is:
4 cores die size +8MB cache die size +memory controller die size +PCI-express die size
If you cut the die size in two you have:
2 cores die size +4MB cache die size + 0,5 memory controller die size + 0,5 PCI-express die size
So you have to
add to the 148mm2 figure + (0,5 memory controller die size) + (0,5 PCI-express die size)
So for the 32nm shrinks (with the info we had prior IDF), the Clarkdale would have bigger size in relation with the die size of a 32nm 8200 with 4MB native cache.
At the time of writing i guess most of the people (except those that work for Intel or guys like Tech sites reviewers) didn't know that the memory controller isn't on the CPU die but on the GPU die instead (and according to other sites the same is true for the PCI-express also).
So at the time of writing with the info that we had avaliable the calculation is correct.
Later IDF came and along with it came reports from various tech sites that said that the memory controller and the PCI-express is not intergrated to the CPU die but to the GPU die. (this is the
only reason that the 32nm Nehalem CPU version die is lower than a 32nm 8200 4MB version die)
So yes, with this
new info it is
easy for everyone to figure out which die is bigger.
Sadly when i wrote my original post those info was
not avaliable.