Integral

[CripplerCrossface]

CAn someone do the integral of e^x^2? I dont think its possible so Im not going to fudge with it. If it can be done holla at me.

 

[xyion]

that equals e^(2x), and that can be integrated. Its a property of e.

 

[Buzzman151]

why are you doig this now?? shouldn't you be go'in out w/ some hoez or something??

 

[CripplerCrossface]

r u sure. i dont think u can just bring it down like that. now if the problem WAS e^(2x) it would be easy but e^(2x) /= e^(X^2). Unless you are using some kinda formula I dont know aboot.

 

[klah]

Ti-89 says no.

 

[CripplerCrossface]

Originally posted by: Buzzman151
why are you doig this now?? shouldn't you be go'in out w/ some hoez or something??

that friday night dawg. then I go hit the bong with the white boys.

 

[klah]

Maple gives this:

1/2*Pi^(1/2)/(-ln(e))^(1/2)*erf(sqrt(-ln(e))*x)

 

[CripplerCrossface]

Originally posted by: klah
Maple gives this:

1/2*Pi^(1/2)/(-ln(e))^(1/2)*erf(sqrt(-ln(e))*x)

whoa. I'm really not f'ing with that. thanx tho.

 

[bleckywelcky]

Originally posted by: xyion
that equals e^(2x), and that can be integrated. Its a property of e.

No, No, No!

That is completely, absolutely, 100% invalid. Basic algebra rules.

e^x^2 != e^2x

What we do not have:
---------------------------

(e^x)^2 = (e^x) * (e^x)

Bases are the same, so add the exponents,

x + x = 2x

(e^x) * (e^x) = e^(x + x) = e^2x

What we do have:
----------------------

e^(x^2) = e^(x * x)

e^(x * x) != e^(x + x)

You can not easily integrate the e^(x^2) function because you have a power, then a chain, then a power on this exponent function. Your teacher/professor will usually never ask you to do an indefinite evaluation on that function. However, they may give you that function and ask you to do a definite evaluation. In which case, you should use whatever program you have loaded onto your calculator or computer to evaluate the indefinite integral with a number of divisions, N, that will meet your error requirements (that N value would be calculated seperately).

-

 

[CripplerCrossface]

Originally posted by: bleckywelcky

Originally posted by: xyion
that equals e^(2x), and that can be integrated. Its a property of e.

No, No, No!

That is completely, absolutely, 100% invalid. Basic algebra rules.

e^x^2 != e^2x

What we do not have:
---------------------------

(e^x)^2 = (e^x) * (e^x)

Bases are the same, so add the exponents,

x + x = 2x

(e^x) * (e^x) = e^(x + x) = e^2x

What we do have:
----------------------

e^(x^2) = e^(x * x)

e^(x * x) != e^(x + x)

You can not easily integrate the e^(x^2) function because you have a power, then a chain, then a power on this exponent function. Your teacher/professor will usually never ask you to do an indefinite evaluation on that function. However, they may give you that function and ask you to do a definite evaluation. In which case, you should use whatever program you have loaded onto your calculator or computer to evaluate the indefinite integral with a number of divisions, N, that will meet your error requirements (that N value would be calculated seperately).

-

Dag u aint have to do it like that. u sound like a bloody prof. i bet you would have typed in red if u could.

 

[Buzzman151]

wah..... i duno wtf these guys are talk'n about.. i get beer + beer +beer^vodka = hella fun

 

[bleckywelcky]

Originally posted by: CripplerCrossface
Dag u aint have to do it like that. u sound like a bloody prof. i bet you would have typed in red if u could.

lol! Sorry, that guy just sounded like he was really sure that you could do something like that. I guess I was apalled? Dunno, heh. Just loved (and still love) my math classes I've had throughout the various years, so I hold the subject very near and dear to my heart Wanted to make sure no one else would be tripped up by that. And yeh, I woulda put the Nos in red if I could have

-

 

[CripplerCrossface]

Originally posted by: bleckywelcky

Originally posted by: CripplerCrossface
Dag u aint have to do it like that. u sound like a bloody prof. i bet you would have typed in red if u could.

lol! Sorry, that guy just sounded like he was really sure that you could do something like that. I guess I was apalled? Dunno, heh. Just loved (and still love) my math classes I've had throughout the various years, so I hold the subject very near and dear to my heart Wanted to make sure no one else would be tripped up by that. And yeh, I woulda put the Nos in red if I could have

-

lol. tru. i wish i had the same desire towards math.

 

[CripplerCrossface]

Originally posted by: Buzzman151
wah..... i duno wtf these guys are talk'n about.. i get beer + beer +beer^vodka = hella fun

Beer + Beer - (2Beer + lunch) +/- hoes = fun

 

[Buzzman151]

Beer + Beer - (2Beer + lunch) +/- hoes = fun

No No No No NO!

It's... Beer + Beer - (2Beer + lunch) +hoes - (old hoez)^(1/2) + (big boobies) = fun for the whole family

 

[CripplerCrossface]

Originally posted by: Buzzman151

Beer + Beer - (2Beer + lunch) +/- hoes = fun

No No No No NO!

It's... Beer + Beer - (2Beer + lunch) +hoes - (old hoez)^(1/2) + (big boobies) = fun for the whole family

lol. tru.