 Jun 24, 2002
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CAn someone do the integral of e^x^2? I dont think its possible so Im not going to fudge with it. If it can be done holla at me.
Originally posted by: Buzzman151
why are you doig this now?? shouldn't you be go'in out w/ some hoez or something??
Originally posted by: klah
Maple gives this:
1/2*Pi^(1/2)/(ln(e))^(1/2)*erf(sqrt(ln(e))*x)
Originally posted by: xyion
that equals e^(2x), and that can be integrated. Its a property of e.
Dag u aint have to do it like that. u sound like a bloody prof. i bet you would have typed in red if u could.Originally posted by: bleckywelcky
Originally posted by: xyion
that equals e^(2x), and that can be integrated. Its a property of e.
No, No, No!
That is completely, absolutely, 100% invalid. Basic algebra rules.
e^x^2 != e^2x
What we do not have:

(e^x)^2 = (e^x) * (e^x)
Bases are the same, so add the exponents,
x + x = 2x
(e^x) * (e^x) = e^(x + x) = e^2x
What we do have:

e^(x^2) = e^(x * x)
e^(x * x) != e^(x + x)
You can not easily integrate the e^(x^2) function because you have a power, then a chain, then a power on this exponent function. Your teacher/professor will usually never ask you to do an indefinite evaluation on that function. However, they may give you that function and ask you to do a definite evaluation. In which case, you should use whatever program you have loaded onto your calculator or computer to evaluate the indefinite integral with a number of divisions, N, that will meet your error requirements (that N value would be calculated seperately).

Originally posted by: CripplerCrossface
Dag u aint have to do it like that. u sound like a bloody prof. i bet you would have typed in red if u could.
Originally posted by: bleckywelcky
Originally posted by: CripplerCrossface
Dag u aint have to do it like that. u sound like a bloody prof. i bet you would have typed in red if u could.
lol! Sorry, that guy just sounded like he was really sure that you could do something like that. I guess I was apalled? Dunno, heh. Just loved (and still love) my math classes I've had throughout the various years, so I hold the subject very near and dear to my heart Wanted to make sure no one else would be tripped up by that. And yeh, I woulda put the Nos in red if I could have

Beer + Beer  (2Beer + lunch) +/ hoes = funOriginally posted by: Buzzman151
wah..... i duno wtf these guys are talk'n about.. i get beer + beer +beer^vodka = hella fun
Beer + Beer  (2Beer + lunch) +/ hoes = fun
Originally posted by: Buzzman151
Beer + Beer  (2Beer + lunch) +/ hoes = fun
No No No No NO!
It's... Beer + Beer  (2Beer + lunch) +hoes  (old hoez)^(1/2) + (big boobies) = fun for the whole family