Instead of comparing length

[schneiderguy]

Shouldn't we be comparing total volume instead? :hmm:

 

[IceBergSLiM]

comparing length of what?

 

[SandEagle]

You'd probably still fail

 

[schneiderguy]

comparing length of what?

Penis, of course.

I think total volume is a better measure of overall manliness than just length or girth alone.

 

[SlitheryDee]

Not when depth of penetration is the most important aspect of its use.

 

[moshquerade]

Penis, of course.

I think total volume is a better measure of overall manliness than just length or girth alone.

can you fill a cup or something?

 

[Heller]

here we go again, another shitty thread from schniederguy

 

[rcpratt]

Length is more important than girth, but girth would have more of an effect on volume of a roughly cylindrical object. I reject your proposition.

Not that some girth isn't important.

 

[IceBergSLiM]

Not when depth of penetration is the most important aspect of its use.

lol you need to ask some women how they feel about pencil dick. The long and skinny is no good. useless without girth

 

[MotF Bane]

can you fill a cup or something?

More likely a thimble.

 

[erikistired]

can you fill a cup or something?

i can. *wink wink nudge nudge*

 

[schneiderguy]

6.5" length
5.5" girth = 2 pi * r => r = .87"

area of base = pi * r^2 = 2.4 inch^2
volume = area of base * length = 15.65 inch^3

Here's mine, assuming the penis is a cylinder.

 

[dank69]

Is it bigger than a baby's arm?
Can you fill Kim Kardashian's cup with it?
Can you put a hat on it and drive in the HOV lane?

 

[MotF Bane]

OP: a lot of people struggle with estimating single dimensions (i.e. how long is 9 inches), but now you'd be asking them to consider three dimensions for visualization. Their heads might explode.

 

[rcpratt]

6.5" length
5.5" girth = 2 pi * r => r = .87"

area of base = pi * r^2 = 2.4 inch^2
volume = area of base * length = 15.65 inch^3

here's mine, assuming the penis is a cylinder.

tmi.

 

[Blackjack200]

6.5" length
5.5" girth = 2 pi * r => r = .87"

area of base = pi * r^2 = 2.4 inch^2
volume = area of base * length = 15.65 inch^3

Here's mine, assuming the penis is a cylinder.

edit: nm

 

[schneiderguy]

tmi.

:awe: What's yours??

 

[moshquerade]

:awe: What's yours??

wow...

have we ever had an actual "comparing sizes" thread on here?
and, sadly, it would never be truthful. :|

 

[MotF Bane]

6.5" length
5.5" girth = 2 pi * r => r = .87"

area of base = pi * r^2 = 2.4 inch^2
volume = area of base * length = 15.65 inch^3

Here's mine, assuming the penis is a cylinder.

And if your girth calculation was off by just .1 inches (less than 1/8), then your final value is off by nearly 3/4 of a cubic inch. Measurement errors, already a major problem in any study of male penis size, will become a vastly, erm, larger issue.

 

[schneiderguy]

wtf, you don't multply by pi before you square it.

your base would be 2.4 inches.

Isn't that what I wrote :hmm::hmm:

 

[rcpratt]

wtf, you don't multply by pi before you square it.

your base would be 2.4 inches.

That's...what it says.

 

[MotF Bane]

wow...

have we ever had an actual "comparing sizes" thread on here?
and, sadly, it would never be truthful. :|

There probably has been a size thread, in fact, I'd guess a few of them... but the problem is a total lack of truthfulness. Being ATOT, the 10+ inch category would run away with it.

 

[Blackjack200]

Isn't that what I wrote :hmm::hmm:

Yes, misread it.

 

[rcpratt]

wow...

have we ever had an actual "comparing sizes" thread on here?
and, sadly, it would never be truthful. :|

To be honest, I've never measured girth. Who keeps a tape measure around? I imagine it's average.

 

[MotF Bane]

Also, OP, I don't know about you, but mine isn't a perfectly straight featureless cylinder. Your calculations can't take that into effect - you'd be better off using mosh's cup comment as an inspiration to calculate displacement.