HELP!!!! Calculus problem

[Warthog912]

IF any of you know anything about integrating please try this problem and see what you get if you have the time or get the chance. Much thanks!

integrate sin(squared)x(cos(squared)x)
-----------------------------------------
sin(x)

 

[rgwalt]

Remember sin^2 + cos^2 = 1

should simplify the integral and you can take it by parts.

Or just use integral tables.

Ryan

 

[churchdoesmatter]

the asnwer is - (cos(x))^3 divided by 3

 

[Warthog912]

Thanks Ryan , you have given me a start to the problem atleast but I don't know what integral tables are????

 

[churchdoesmatter]

<< Remember sin^2 + cos^2 = 1 >>



his question was sinx^2 TIMES cosx^2

 

[silverpig]

Yeah, but you can use sin^2 + cos^2 = 1 to get sin^2 = 1 - cos^2. Then sub that in for sinx... he was giving him direction...

 

[gwlam12]

<< Yeah, but you can use sin^2 + cos^2 = 1 to get sin^2 = 1 - cos^2. Then sub that in for sinx... he was giving him direction... >>

 

[Viper GTS]

sin²(x)cos²(x)

Use alt-0178 for the ², it comes in handy. Alt-0179 will give you a convenient ³ as well.

Viper GTS

 

[Darien]

Hope this helps...

¡&ograve;((sin©÷x)(cos©÷x))/sinx dx

=¡&ograve;((sin©÷x)(1-sin©÷x))/sinx dx

=¡&ograve;sinx dx - ¡&ograve;sin©&oslash;x dx

=¡&ograve;sinx dx - ¡&ograve;(1-cos©÷x)(sinx) dx
----->let u = cosx
----->du = -sinx dx

=¡&ograve;sinx dx - ¡&ograve;(1-u©÷) -du

=¡&ograve;sinx dx + ¡&ograve;(1-u©÷)du

= -cosx + u - u©&oslash;/3 + C

= -cosx + cosx - u©&oslash;/3 + C

= -cos©&oslash;x/3 + C

Hopefully typed in everything correctly.

Have a nice day

Darien

=====

EDIT = after checking the post, i see that all those nifty integral symbols and those ^2 and ^3 have been changed. argh.

sorry 'bout that.

 

[Warthog912]

hey guys,
thank yall soooo much not only do i have the answer, i understand. And by the way this actually isn't Warthog either, this is his girlfriend. Yall are great. I'll have to come back if i have more questions.
Thanks again.