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Does 2.9999999~9 = 3

You are obviously confused. Infinitely small does not equal zero.


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Originally posted by: virtualgames0
Originally posted by: Supa
Does 0.000000 .... 00001 = 0 ?


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Are you dumb?
0.0000.. forever wouldn't let you have a 1 at the end, because there IS NO END.

 
Originally posted by: Supa
You are obviously confused. Infinitely small does not equal zero.


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Originally posted by: virtualgames0
Originally posted by: Supa
Does 0.000000 .... 00001 = 0 ?


----

Are you dumb?
0.0000.. forever wouldn't let you have a 1 at the end, because there IS NO END.

he wasnt confused. your question is stupid and makes no sense. you wrote .000... which means repeat that expression forever. if 000 is repeated forever, how do you end up with a 1 on the "end"?

oh, and the answer is yes.

.999... = 1, so 2.999... = 3. its not a hard concept.
 
he wasnt confused. your question is stupid and makes no sense. you wrote .000... which means repeat that expression forever. if 000 is repeated forever, how do you end up with a 1 on the "end"?

The chain eventually ends at a termination point but it usually isn't a 1. It's an anchor.

Cheers!
 
Here's a proof.

x = .999999~9
10x = 9.9999999~9

10x - x = 9.99999~9 - .99999~9
9x = 9
x = 1.

So, 2 + .9999~9 = 2 + 1 = 3.

I think this is actually kind of a paradox. 2.9999~9 does not *actually* equal 3, since it is approaching 3, but using simple math you can argue it does equal 3. I'm not EXACTLY sure, but I think this is just a flaw within the decimal number system humanity uses. It's been too long ago since I read this in a book (I was browsing) so I can't recall.

This is also an interesting POV of the same problem.

1/9 = .1111~1
2/9 = .2222~2
....3/9 4/9 5/9 etc.
8/9 = .8888~8
9/9 = .9999~9

Except we also know that 9/9 = 1 😛
 
Well the logic (I guess) is as similar to this:

X =.999999999999999999999999999999
10X=9.9999999999999999999999999999
(10X)-(X)=9
9X=9
x=1


Only flaw is adding like terms..





 
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