cool phone number trick

[Gibson486]

it got my cell phone number wrong.....it reveresed the 0 and the 9.

 

[Maximus96]

Originally posted by: Gibson486
it got my cell phone number wrong.....it reveresed the 0 and the 9.

haha, you suck at teh math.

 

[klah]

Originally posted by: Maximus96
1. take the first 3 digit of your phone number (not the area code)
2. multiply by 80
3. add 1
4. multiply by 250
5. add the last 4 digits of your phone number
6. add the last 4 digits again
7. subtract 250
8. divide by 2

what do you get?

1. x
2. 80x
3. 80x +1
4. 20,000x + 250
5. 20,000x + 250 + y
6. 20,000x + 250 + 2y
7. 20,000x + 2y
8. 10,000x +y

 

[Aharami]

pretty cool

 

[vrbaba]

Originally posted by: quakefiend420
that's kinda neat

i hope with over 8000 posts ur kidding.

multiply ur first three numbers by 10000and adding ur last 4 digits, gives u the same number,

 

[Maximus96]

Originally posted by: klah

Originally posted by: Maximus96
1. take the first 3 digit of your phone number (not the area code)
2. multiply by 80
3. add 1
4. multiply by 250
5. add the last 4 digits of your phone number
6. add the last 4 digits again
7. subtract 250
8. divide by 2

what do you get?

1. x
2. 80x
3. 80x +1
4. 20,000x + 250
5. 20,000x + 250 + y
6. 20,000x + 250 + 2y
7. 20,000x + 2y
8. 10,000x +y

yet people still get it wrong...

 

[vrbaba]

Originally posted by: vrbaba

Originally posted by: quakefiend420
that's kinda neat

i hope with over 8000 posts ur kidding.

multiply ur first three numbers by 10000and adding ur last 4 digits, gives u the same number,

EDIT: klah beat me to the punch 😛

 

[Ricemarine]

heh... I got my phone #...

 

[EyeMWing]

45937...

Lets try that again.

45937.

You cannot do it in a single computation - order of operations breaks it. You have to run each step seperately to ignore OOO. Worthless parlor trick.

 

[jonnyGURU]

OMG!! They know my phone number! It's the popocalips!!! The four hornmen of the popocalips!!!!

 

[cyberhap]

867-5309

 

[AdamSnow]

woW! It's my fone number!

 

[klah]

Originally posted by: cyberhap
867-5309

hi Jenny.

A/L?

 

[aolj]

Pretty good algorithm.

So you're pretty much multiplying 10,000 with your first three digits and adding your last four digits.

 

[MobiusPizza]

It's nothing fancy. Anyone who can do algebra can proof that 🙂

Let first three digits of your phone number be x
And last 4 digits of your phone number be y

So that your phone number is actually 10000*x + y
Say your number is 123 4567
123 * 10000 + 4567 = 1234567

Now the formula:

"Take first 3 digits multiply by 80, add 1 then times the result by 250, add last 4 digits 2 times, minus result by 250 and divide the result by 2" can be written as follows:

[(80x + 1)*250 +2y - 250] / 2

= [20000 x + 250 + 2y - 250] / 2
=(20000x + 2y) / 2
= 10000x + y
= your original phone number

These tricks can be formulated with any set of numbers easily if you spend a little time on formulating them.

 

[MobiusPizza]

Originally posted by: aolj
Pretty good algorithm.

So you're pretty much multiplying 10,000 with your first three digits and adding your last four digits.

arg I was a step late :/

 

[Juice Box]

omg hax

 

[Proposition Ed]

awesome!

 

[chuckywang]

Anybody who says this is awesome needs to go back to middle school and learn algebra.

 

[shuan24]

800-8135

 

[imported_Phil]

42.

 

[Appledrop]

holy batman.. i put my phone number in, and i got my phone number back! :shocked:

 

[thecrecarc]

well, didint work for me. and i did everything correctly

 

[dullard]

Ok try this:
[*]Take any number.
[*]Add 1.
[*]Subtract 1.
[*]What do you get?
Wow, you get your number back. :roll: These stupid formulas really just show how bad most people are at math.

 

[ondarkness]

Originally posted by: AnnihilatorX
It's nothing fancy. Anyone who can do algebra can proof that 🙂

Let first three digits of your phone number be x
And last 4 digits of your phone number be y

So that your phone number is actually 10000*x + y
Say your number is 123 4567
123 * 10000 + 4567 = 1234567

Now the formula:

"Take first 3 digits multiply by 80, add 1 then times the result by 250, add last 4 digits 2 times, minus result by 250 and divide the result by 2" can be written as follows:

[(80x + 1)*250 +2y - 250] / 2

= [20000 x + 250 + 2y - 250] / 2
=(20000x + 2y) / 2
= 10000x + y
= your original phone number

These tricks can be formulated with any set of numbers easily if you spend a little time on formulating them.

😕