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C Programmers, please help with small program

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int main (void) {
int i, j,SUM=0;
for (i=1;i<10000, i++) {
for (j=1;j<i, j++) {
if(i % j) == 0 {
SUM+= j
}
if sum == i then {
printf(" %d", SUM);
}
sum = 0;
}
return 0;
};
 
The purpose of that loop is to check each j value to modulus with i, but any more then that I am not sure what it idoes..
 
Originally posted by: Aznguy1872
The purpose of that loop is to check each j value to modulus with i, but any more then that I am not sure what it idoes..
Click to expand...

according to the code, there is nothing inside the brackets, so nothing gets done in that for loop. Once the loop is done, j is the value i-1, then you are checking if (i % (i-1) ==0)
 
Originally posted by: JetBlack69
Originally posted by: Aznguy1872
The purpose of that loop is to check each j value to modulus with i, but any more then that I am not sure what it idoes..
Click to expand...

according to the code, there is nothing inside the brackets, so nothing gets done in that for loop. Once the loop is done, j is the value i-1, then you are checking if (i % (i-1) ==0)
Click to expand...


which means I would need an if statement in the brackets for the second for loop?
 
i would take out the sum variable and sit on ur thumb a bit. then i would fix your syntax cuz there are errors all over the damn thing......re evaulate what you want to do here.... i finished writing this prog in under 35 seconds....lets go now...
 
shell:~> gcc test.c
test.c: In function `main':
test.c:3: error: syntax error before ')' token
test.c:4: error: syntax error before ')' token
test.c: At top level:
test.c:8: error: syntax error before string constant
test.c:8: warning: conflicting types for built-in function `printf'
test.c:8: warning: data definition has no type or storage class
test.c:9: warning: data definition has no type or storage class
test.c:10: error: syntax error before '}' token
 
because I am at work Im using this ssh thing to connect to a compiler. I normally use bloodshed Dev ++, when i get home later tonight I'll be able to do more there...
 
Do you know what those mean? You have the same error in line 3 and 4, they are both for loops. You should have a ; instead of a ,
 
Im sorry if I am new at this c programming, this is my first time experience with programming and I am not good with it. But I am trying my best. I am a few chapters behind because of projects and with exams coming up dont make it much easier to get caught up.
 
#include <stdio.h>

int main (void) {
int i, j,SUM=0;
for (i=1;i<10000; i++) {
for (j=1;j<i; j++) {
if(i % j) == 0 {
SUM+= j
}
if (sum == i then) {
printf("%d", SUM);
}
sum = 0;
}
return 0;
};
 
Originally posted by: beggerking
#include <stdio.h>

int main (void) {
int i, j,SUM=0;
for (i=1;i<10000; i++) {
for (j=1;j<i; j++) {
if(i % j) == 0 {
SUM+= j
}
if (sum == i then) {
printf("%d", SUM);
}
sum = 0;
}
return 0;
};
Click to expand...


then is not a keyword.
 
I compiled it and this is the error I get:

test.c: In function `main':
test.c:7: error: syntax error before '==' token

so in line 7.. hrm
 
int main (void) {
int i, j,SUM=0;
for (i=1;i<10000; i++) {
for (j=1;j<i; j++) {
if(i % j) == 0 {
SUM+= j ;
}
if (sum == i then) {
printf("%d", SUM);
}
sum = 0;
}
return 0;
};


need to close the sum+=j

the first sum = 0 is to initialize the sum variable and to set it to 0
then the remaining sum = 0 s resets the sum after every iteration.
 
Originally posted by: Aznguy1872
how come in ur code we declaring that SUM = 0 twice?
Click to expand...

He is declaring SUM 0 a second time for the same reason he declared it 0 the first time.

If he didn't declare SUM 0 the second time, it would contain the results of the previous iteration.
 
I still get an error with that code, I changed the sum to SUM and got rid of the 'then' and i get

test.c: In function `main':
test.c:6: error: syntax error before '==' token
 
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