C Programmers, please help with small program

[JetBlack69]

what is the purpose of this loop?
for (j=1;j<i, j++) {

}

 

[beggerking]

int main (void) {
int i, j,SUM=0;
for (i=1;i<10000, i++) {
for (j=1;j<i, j++) {
if(i % j) == 0 {
SUM+= j
}
if sum == i then {
printf(" %d", SUM);
}
sum = 0;
}
return 0;
};

 

[Aznguy1872]

The purpose of that loop is to check each j value to modulus with i, but any more then that I am not sure what it idoes..

 

[JetBlack69]

Originally posted by: Aznguy1872
The purpose of that loop is to check each j value to modulus with i, but any more then that I am not sure what it idoes..

according to the code, there is nothing inside the brackets, so nothing gets done in that for loop. Once the loop is done, j is the value i-1, then you are checking if (i % (i-1) ==0)

 

[beggerking]

does my modified code work above? dnt have a compiler here so...

 

[Aznguy1872]

I just tried it and I get errors when trying to compile it.

 

[Aznguy1872]

Originally posted by: JetBlack69

Originally posted by: Aznguy1872
The purpose of that loop is to check each j value to modulus with i, but any more then that I am not sure what it idoes..

according to the code, there is nothing inside the brackets, so nothing gets done in that for loop. Once the loop is done, j is the value i-1, then you are checking if (i % (i-1) ==0)

which means I would need an if statement in the brackets for the second for loop?

 

[tmarcum99]

i would take out the sum variable and sit on ur thumb a bit. then i would fix your syntax cuz there are errors all over the damn thing......re evaulate what you want to do here.... i finished writing this prog in under 35 seconds....lets go now...

 

[JetBlack69]

Why don't you tell us the compile errors you are getting Aznguy1872?

 

[Aznguy1872]

shell:~> gcc test.c
test.c: In function `main':
test.c:3: error: syntax error before ')' token
test.c:4: error: syntax error before ')' token
test.c: At top level:
test.c:8: error: syntax error before string constant
test.c:8: warning: conflicting types for built-in function `printf'
test.c:8: warning: data definition has no type or storage class
test.c:9: warning: data definition has no type or storage class
test.c:10: error: syntax error before '}' token

 

[Aznguy1872]

some crazy errors...

 

[Aznguy1872]

because I am at work Im using this ssh thing to connect to a compiler. I normally use bloodshed Dev ++, when i get home later tonight I'll be able to do more there...

 

[JetBlack69]

Do you know what those mean? You have the same error in line 3 and 4, they are both for loops. You should have a ; instead of a ,

 

[Aznguy1872]

Ahh, that i didn't notice.. dang, good catch mate.

 

[Aznguy1872]

Im sorry if I am new at this c programming, this is my first time experience with programming and I am not good with it. But I am trying my best. I am a few chapters behind because of projects and with exams coming up dont make it much easier to get caught up.

 

[beggerking]

#include <stdio.h>

int main (void) {
int i, j,SUM=0;
for (i=1;i<10000; i++) {
for (j=1;j<i; j++) {
if(i % j) == 0 {
SUM+= j
}
if (sum == i then) {
printf("%d", SUM);
}
sum = 0;
}
return 0;
};

 

[JetBlack69]

Originally posted by: beggerking
#include <stdio.h>

int main (void) {
int i, j,SUM=0;
for (i=1;i<10000; i++) {
for (j=1;j<i; j++) {
if(i % j) == 0 {
SUM+= j
}
if (sum == i then) {
printf("%d", SUM);
}
sum = 0;
}
return 0;
};

then is not a keyword.

 

[beggerking]

lol my bad too much vb
ya... try take that then out

 

[Aznguy1872]

I compiled it and this is the error I get:

test.c: In function `main':
test.c:7: error: syntax error before '==' token

so in line 7.. hrm

 

[Aznguy1872]

how come in ur code we declaring that SUM = 0 twice?

 

[beggerking]

int main (void) {
int i, j,SUM=0;
for (i=1;i<10000; i++) {
for (j=1;j<i; j++) {
if(i % j) == 0 {
SUM+= j ;
}
if (sum == i then) {
printf("%d", SUM);
}
sum = 0;
}
return 0;
};


need to close the sum+=j

the first sum = 0 is to initialize the sum variable and to set it to 0
then the remaining sum = 0 s resets the sum after every iteration.

 

[JetBlack69]

if(i % j) == 0 {

needs parenthesis around the if part

if( (i % j) == 0 ) {

 

[JetBlack69]

Originally posted by: Aznguy1872
how come in ur code we declaring that SUM = 0 twice?

He is declaring SUM 0 a second time for the same reason he declared it 0 the first time.

If he didn't declare SUM 0 the second time, it would contain the results of the previous iteration.

 

[Aznguy1872]

I still get an error with that code, I changed the sum to SUM and got rid of the 'then' and i get

test.c: In function `main':
test.c:6: error: syntax error before '==' token

 

[Aznguy1872]

kk let me try ur suggestion jetblack