ATOT, let's see how many of you get this right.

[SSSnail]

 

[MixMasterTang]

4 psi

 

[AMDZen]

4 psi

qft

 

[FuzzyDunlop]

4psi

Now the real question: is that sidewall pressure?

 

[JulesMaximus]

4psi

Now the real question: is that sidewall pressure?

No, that would be 40psi.

 

[newb111]

4psi

 

[Jeeebus]

42

 

[TwiceOver]

Sidewall?

 

[Xecuter]

OMG KIRCHOFFS LAWS

....wait

 

[Anubis]

Pat Buchanan

 

[masterxfob]

4 psi

this

 

[F1N3ST]

4? Uhh....lol

 

[DrPizza]

Doubled the radius = quadrupled the cross sectional area.

 

[Rubycon]

What is the flow rate?
Static would have the same pressure everywhere.

 

[SSSnail]

What is the flow rate?
Static would have the same pressure everywhere.

Flow rate varies, but regulated to 4 PSI constant on both inputs.

 

[Howard]

What is that thingy in the bottom pipe?

 

[SSSnail]

What is that thingy in the bottom pipe?

A thing that is also pushing out 4 PSI.

 

[destrekor]

What is that thingy in the bottom pipe?

Yeah top pipe I'd answer 4psi - it's just increasing volume, not pressure.

Bottom pipe, I have no idea WTH is supposed to be happening.

Is that a wall? Like, 4psi slamming into a wall in a pipe, and somewhere somehow 4psi is on the other side as well?
:hmm:

 

[destrekor]

A thing that is also pushing out 4 PSI.

So...
I'm not very technically oriented, and thus will likely be wrong.

4psi on top image
8psi on bottom image?

 

[SSSnail]

Yeah top pipe I'd answer 4psi - it's just increasing volume, not pressure.

Bottom pipe, I have no idea WTH is supposed to be happening.

Is that a wall? Like, 4psi slamming into a wall in a pipe, and somewhere somehow 4psi is on the other side as well?
:hmm:

Nope. Just another fan that by itself would also put out 4PSI.

 

[destrekor]

Nope. Just another fan that by itself would also put out 4PSI.

does it remain 4psi, or is it exponentially increased?
16psi?

 

[bobsmith1492]

It's just like an electric circuit. Pressure = voltage; flow rate = current.

So for the top one, two 4V supplies are in parallel with a result of 4 volts (4 PSI), but at twice the current (flow rate).

The bottom one is like two 4V supplies in series, giving 8V (8 PSI).

 

[pontifex]

i have no idea wtf the picture even indicates let alone getting whatever it is right...

 

[vshah]

4psi for both?

but then...why do people do push pull on heatsinks?

so i'm going to say 4psi top, 8psi bottom

but then...why would you say "would put out 4psi on its own"

so i think it doesn't add anything since the pressure in the whole tube is already 4psi

so...4psi for both.

 

[SSSnail]

does it remain 4psi, or is it exponentially increased?
16psi?

Think of it as a fan that's blowing 4PSI by itself, regardless of what the input pressure is (of course less than 4PSI), and it is a throughput fan, meaning if inlet pressure is greater than what it can produce then the differential pressure will go through). In this case, the input pressure is already 4 PSI.

I'm just trying to make a point.