Originally posted by: PurdueRy
Originally posted by: Tom
Originally posted by: PurdueRy
Originally posted by: Tom
Originally posted by: jagec
Originally posted by: KK
Think about it, the conveyor belt will never keep up. This question has you believe that it will but no way in hell it could.
It doesn't matter if the conveyor belt can "keep up" or not, the plane takes off. Even if you set it up to move at twice the speed of the airplane in the opposite direction, the plane takes off.
Another example. The plane starts in the air, on a landing approach with the gear down. The conveyor is moving backwards at, oh, 300 MPH. The plane touches down, holding a constant throttle position, rolls to the end of the runway, and lifts off again. As it circles around to make the approach again, we switch the conveyor so it moves FORWARDS at 300mph. Once again our plane touches down, rolls to the end of the runway under constant throttle, and takes off. As long as the pilot didn't do anything silly like touch the brakes, the two approaches would appear identical to an observer on the ground. Maybe a few feet plus or minus, because of rolling resistance, but certainly nothing drastic.
If THAT doesn't demonstrate that groundspeed isn't airspeed, nothing will. Groundspeed (at least in the direction the plane's pointing) only affects airspeed when the brakes are applied!
It's funny, because in your attempt to give an example that proves your point, you actually prove mine !
In your example the conveyor belt has no effect on the speed of the moving plane. That is because the conveyor belt cannot transfer any force to the plane. The plane is moving because it has momentum, the conveyor belt prevents any force in the opposite direction from affecting this momentum.
In the same way, the plane at rest cannot move, because the special condition that it is resting on a device that will prevent any force from having an effect on it's present state at rest.
Again I will refer those that don't understand to my example(as I think it is the easiest to picture).
Take a toy car, wheels are not driven by any motor. Put it on a angled treadmill so that it would roll forward from rest. now turn on the treadmill to go in the opposite direction the car wants to roll in. Make it go as fast as you want but that toy car IS going to roll down the treadmill.
Now, some may say "HEY THAT'S UNFAIR! You're treadmill is declined." You must think of this in terms of forces. The engines apply a force to the plane. In much the same way, gravity applies a very similar force to the car on the treadmill. Both forces are not affected by treadmill speed. Therefore the substitution of gravitational force for the engines thrust is perfectly valid.
Hope that helps you guys picture it.
You keep trying to introduce external forces that don't exist in the original scenario. An inclined plane is an external force of gravity.
As I stated before, the plane engines are not an external force. They are part of the plane .
If this was a car and not a plane, I bet you would readily concede that it wouldn't matter how powerful the car was, that as long as the conveyor matched the speed of the wheels in the opposite direction, that the car would not move releative to anythnig but the belt.
The airplane behaves exactly the same way. It doesn't matter that the wheels are not "driven" by the powerplant, the fact is the wheels have to move for the plane to move, and they can't move relative to anything but the conveyor belt, just like in the car scenario.
Tell me how the force of gravity acts different on the place than its own engines do
I didn't say it acts differently, i said it's an external force, whereas the engines are part of the system that includes the plane and the wheels, and the conveyor belt.
