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YACQT (yet another circuit question thread)

Originally posted by: esun
How about this:

- I_1 + V_c/R_3 = I_s

Just use KCL: currents at a node must sum to zero.
Click to expand...

Yeah, use KCL for everything. If you know the node voltages, turn them into currents by doing (V1-V2)/R. Just make sure to keep all your polarities lined up.
 
Originally posted by: esun
How about this:

- I_1 + V_c/R_3 = I_s

Just use KCL: currents at a node must sum to zero.
Click to expand...

How do you know the direction of V_c/R_3 current?

Couldn't you do a source transform on the current source and turn it into a voltage source?
Click to expand...

what?
 
-Vs + I1 x (R1+R2) + (I1+Is) x R3 = 0

There's a lot of ways to solve for I1. esun's way is correct also.
 
Originally posted by: RESmonkey
Originally posted by: slackwarelinux
Couldn't you do a source transform on the current source and turn it into a voltage source?
awesome paint picture
Click to expand...

wait, how does a resistor in parallel w/ a current source turn into a voltage source?
Click to expand...

My drawing was pretty bad, but it turned into a voltage source in series with a resistor.



source transformations, taught by a professor who sounds like kermit the frog

start at around 1:22 for the source transforms
 
Yeah since you have the node voltages, all you should need to use is Ohm's law and P=IV

For example, I1 is the current through R1, so I1=(Va-Vb)/R1=-0.476mA
 
I think I understand now; the current source just injects current for R3. I wrote a KVL and am gonna try and solve it.
 
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