Why does a a jump from 880 to 900 cause freeze-ups?

[BlazingSaddles]

I had my cel2 533A overclocked to 880 (8.5*110) with 1.7v. I had ran many tests on it to determine stability (burnbx, burnp6 overnight, stability test overnight), and then, today I tried 900 mhz, using 1.7v. I can boot up and run some programs fine (I am typing this now on 900), but if I run burnbx+burnp6, after 10 min or so, the computer freezes. What could be the problem, I thought if I kept the voltages the same, no more heat was generated than 880mhz. Anyway, my system is pretty well cooled, so I don't think heat is really a problem. Does the processor just need a little more power (1.75v)?

 

[BlazingSaddles]

^

 

[Painman]

I would say so. Bumping up .05v isn't going to create any kind of real heat problem, especially if it is well cooled as you say. If you have a decent heatsink like a golden orb, Alpha, etc. you will be fine.

Oh yeah, the multiplier on your chip is 8.0, not 8.5

-Pain

 

[MF1]

You've probably already answered your own question. Be careful, limit at 10% increased.

 

[obeseotron]

There is some point when a CPU simply becomes unstable. My Celron 366 will do 567 (103FSB) at 2.2v fine, but 577 (105FSB) becomes much sketchier. By all means try up to .3v above the intended voltage, but what you got is about right for your chip.