Divide a pie into three pieces. 1/3 = .333333333333333
Where did the .000000000000000001 go?
Divide a pie into three pieces. 1/3 = .333333333333333
Where did the .000000000000000001 go?
Divide a pie into three pieces. 1/3 = .333333333333333
Where did the .000000000000000001 go?
How much less?Well, .9(9repeating) is still not 1. It's still less than 1.
This whole thing is so much fail because these people are too high up on their horses to realize that dividing by 3 still means you have, at the end of the day, a .xxxxxxxx4 somewhere because you're truncating. If you're going to say that 1/3+1/3+1/3 = 1. Then sure, that's fine. But the minute you make it a repeating decimal and don't round one of the results to a .xx4, fail.
A friend of mine posted one of her other vids on Facebook the other day and I went and watched several of them, including this one. I must say they are very entertaining and she is one damn smart woman. If more math teachers could be like her then more of us would enjoy math, she makes it fun.
Well I know when I cut pie into 3 pieces, crumbs fall behind.

Then you'd lose part of the pie to the heat =Pwhat if we were to freeze that Pie in LN2, and then slice it evenly with a heat beam?
![]()
what if we were to freeze that Pie in LN2, and then slice it evenly with a heat beam?
![]()
Then you'd lose part of the pie to the heat =P

hmm, okay, that's actually worse than not freezing it and "losing" crumbs...
OK, how about we freeze the pie in LN2, and then chip it with a hammer? we have chunks of pieces, crumbs and what-not, that can "easily" be scooped up and total 3 complete slices, without any real, physical loss.
even with the crumbs in a dry pie, the crumbs are still there, on the plate....so it's not like they are ever lost.
![]()
In all seriousness, the problem with this "dilemma"
is that 1/3 != 0.3333333333(repeating). 0.3333333(repeating) is the closest numerical value to the fraction 1/3, and thus is used for it.
Same as in calculus when limits are used with infinities, X values converage to Y values and can be mathmatically considered Y because they are the closest numerical value for it, when in reality they are not.
Yet, on a molecular level, I bet pieces of the pie were left behind. pieces too small to really see, and unless using a vacuum or chemical solvent would not be able to get them off.
And since 0.9999(repeating) is such a tiny, little fraction from 1, a single atom can be theorized to push it over the edge. Thus still meaning you cannot get a full pie when scooping it either.

Divide a pie into three pieces. 1/3 = .333333333333333
Where did the .000000000000000001 go?
Yet, on a molecular level, I bet pieces of the pie were left behind. pieces too small to really see, and unless using a vacuum or chemical solvent would not be able to get them off.
And since 0.9999(repeating) is such a tiny, little fraction from 1, a single atom can be theorized to push it over the edge. Thus still meaning you cannot get a full pie when scooping it either.
What is the mass that is lost during heat loss?*sigh* it is NOT a tiny, little fraction from 1, it is EXACTLY equal to one. Perfectly equal, not a bit of a difference.
And, with the pie, if you freeze it, you remove energy. Thanks to E=mc², you've lost some pie. Yes, E=mc² applies to chemical reactions, etc.; it's not limited in scope to nuclear reactions, though when you take the little bit of energy and divide by c², it's an incredibly tiny amount of mass.
*sigh* it is NOT a tiny, little fraction from 1, it is EXACTLY equal to one. Perfectly equal, not a bit of a difference.
And, with the pie, if you freeze it, you remove energy. Thanks to E=mc², you've lost some pie. Yes, E=mc² applies to chemical reactions, etc.; it's not limited in scope to nuclear reactions, though when you take the little bit of energy and divide by c², it's an incredibly tiny amount of mass.
In all seriousness, the problem with this "dilemma"
is that 1/3 != 0.3333333333(repeating). 0.3333333(repeating) is the closest numerical value to the fraction 1/3, and thus is used for it.
Same as in calculus when limits are used with infinities, X values converage to Y values and can be mathmatically considered Y because they are the closest numerical value for it, when in reality they are not.
Watch the video!
If you can't describe a number that fits between two numbers, then those two numbers are equal. It follows that 1/3 = 0.3333333333(repeating).
The problem with this "dilemma" is solved by your own assertion!![]()
Watch the video!
If you can't describe a number that fits between two numbers, then those two numbers are equal. It follows that 1/3 = 0.3333333333(repeating).
The problem with this "dilemma" is solved by your own assertion!![]()
