• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Where is the best place to get a cheap fan??

Ravven

Member
I've been looking around quite bit and it seems that shipping at most places is as expensive as the fan itself. I want to replace the fan on my Globalwin WBK38 'cause it's just unbearable!!!!! I can't even sleep with my computer on. I want a decent 60mm fan that is relatively quiet. Right now, my fan specs are:

GlobalWin Fan (double ball bearing)
Fan Specs: 25x60x60mm, 12V, 6800RPM, 46.5 dBa
HS Dimensions: 42x63x75mm

Can anyone recommend a replacement fan and where to get it cheap??

Thanks in advance,

ravven
 
You might try grounding the fan to the +5V line from the PSU instead of to a ground line. That drops it to 7 volts, with about a proportionate drop in airflow and RPM (and therefore noise). It's not dreadfully hard to do if you're used to dabbling with electricity, and it's free... otherwise try phamcomputer.com, they carry a range of 60mm Adda fans down to some very quiet ones, or find a Panaflo L1A or M1A 60mm (maybe caseetc.com).
 
Damn, I never really thought of messing with the fan myself....From the spec sheet for the fan, I figure that the internal resistence is about 38 ohms...couldn't I just put a variable resistor on the red power line and throttle the fan that way? I'm guessing this would work, right? Any help would be greatly appreciated in answering this question for me or the original one as to where to cheaply purchase a fan 😀

Thanks

Ravven
 
Originally posted by: Ravven
I'm guessing this would work, right?

Yes, it will work no matter which line you put it on, you are just creating 2 voltage drains in series with 12 V source. But with the 7 V mod you usually don't need to cut or buy anything. All you need is to switch the black plug with one of the red.
 
Keep checking sites regularly. From time to time they offer free shipping.

And, as much as they suck, CompUSA carries Vantec Stealths, which will definately quiet your system down.

Also, if you know a small PC parts retailer, and get to talking to them about the fans you want, you might just encourage them to make a large order, and begin stocking them. Sure, they'd charge about 3-4 dollars more than most sites do, but it's still cheaper in the end.
 
Thanks for the ideas...I forgot to mention that it was a 3 pin connector fan, so the 7V mod wouldn't work. What I ended up doing was just picking up a 15-turn 1K Cermet potentiometer at Radioshack and putting it in series with the fan. It works really nicely and I can pretty much adjust the fan from 6800 rpm to 0. I just don't know if the potentiometer will hold out for long...seemed to be getting pretty hot. Anyone know if this is really a long term solution? I don't want the potentiometer to burn out in the middle of the night and then for my t-bird to fry when the fan stops.

Thanks,

ravven
 
beatle's suggestion is good, but the rheostat will cost as much as a fan, and just as much to ship. Radioshack may have that rheostat, too. Or measure the resistance of your cermet potentiometer when you get the fan speed right, go back to the shack and get a 5watt resistor of the value you need, or any 5watt rheostat that goes that high... You fan draws .32amps X12volts= 3.84watts, so the cermet won't last long.....

Radioshack carries 60mm fans, too, whatever they have is likely a lot less noisy than what you have- check the power/rpm ratings...
 
but isn't my potentiometer only really putting out like .857 Watts? power = current * voltage, right? My fan usually ran at 6800 RPM, now it's running at 4500. I figured that the internal resistence of the fan was 38 ohms, using this figure, I was able to figure out that the potentiometer resistence is only at 20 ohms. Therefore the current through the curcuit is 12V/(20+38) = .207 A. The power at the potentiometer is .207 * 4.14 = .857 Watts. Shouldn't this be fine for the potentiometer eventhough it's only rated for .75 Watts? Should I definately search for another rheostat?

thanks,
ravven
 
Hi,

This is my first post so bear with me.

I could be worng but I don't think that you can calculate the current through the curcuit like that, because of the potentiometer the voltage at the fan is not 12v. I would use power = (current)^2 * resistence. Using the max current of the fan (~.32amps) and the resistence of the potentiometer (20 ohms) you get 2.05 watts. You should get another rheostat.

 
Back
Top