What's the next number in this sequence

deftron

Lifer
Nov 17, 2000
10,868
1
0

1 ... 4 ... 7 ... 11 ... 15 ... 18 ... 21 ... 24 ... 27 ...



What's the next number in the sequence?
Please explain why , too.



 

deftron

Lifer
Nov 17, 2000
10,868
1
0
When I said "very tough math problem"

I should have said ""very tough problem for anyone who knows math"

 

Otaking

Diamond Member
Mar 13, 2000
5,219
0
0
Originally posted by: Vaerilis
31

1 - 4 - 7
11 - 15 - 18
(2)1 - (2)4 - (2)7
(3)1 - (3)5 - (3)8

Probably.

That's amazing. Even though the answer was wrong, I never saw that pattern. :beer:

 

deftron

Lifer
Nov 17, 2000
10,868
1
0
Originally posted by: Otaking
Originally posted by: Vaerilis
31

1 - 4 - 7
11 - 15 - 18
(2)1 - (2)4 - (2)7
(3)1 - (3)5 - (3)8

Probably.

That's amazing. Even though the answer was wrong, I never saw that pattern. :beer:


That's the obvoius (wrong) answer ...



 

EngenZerO

Diamond Member
Dec 24, 2001
5,099
2
0
" The Jan-Feb puzzle asked you to give the next item in this series:

1, 4, 7, 11, 15, 18, 21, 24, 27...

A bit of lateral thinking required here, as it was not really a Maths puzzle at all. The solution lies in the number of letters in the English names for these numbers. 73 (SEVENTYTHREE) is the answer "

http://www.bogle-dw.freeserve.co.uk/mtmt01.htm
 

deftron

Lifer
Nov 17, 2000
10,868
1
0
Originally posted by: ribbon13
a(n) when spelled is the smallest positive integer > a(n-1) with exactly n letters.

Yeah ... like I said ... nice Googling

%S A084390 1,4,7,11,15,18,21,24,27,73,101,104,107,111,115,118,121,124,127,173,323,
%T A084390 373,1104,1107,1111,1115,1118,1121,1124,1127,1173,1323,1373,3323,3373,
%U A084390 11373,13323,13373,17373,23323,23373,73373,101373,103323,103373,111373
%N A084390 a(n), when spelled in English, is the smallest positive integer > a(n-1) with exactly n letters.
%C A084390 This uses the conventions that "and" is never used, and two-digit numbers are not used before "hundred". The sequence is labeled "finite" because there is no widely accepted naming convention for arbitrarily large numbers. - David Wasserman (wasserma(AT)spawar.navy.mil), Dec 20 2004
%H A084390 Author?, <a href="http://groups.google.com.au/groups?hl=e...3a57%2540posting.google.com%26rnum%3D6">Title?</a>
%H A084390 Author?, <a href="http://groups.google.com.au/groups?hl=e...%252C4%252C7%252C11%252C15%252C18%2522">Title?</a>
%e A084390 a(5) = 7 because 'seven' has 5 letters

Link



Even if you were part of that, you wouldn't use the same phrase verbatim :roll:
 

ArmenK

Golden Member
Oct 16, 2000
1,600
1
0
Originally posted by: deftron
When I said "very tough math problem"

I should have said ""very tough problem for anyone who knows math"

Why do you need to know math for this problem? If anything you need to not think about math to solve it since it requires counting letters in words.