Originally posted by: Confused
However it won't come down "at the same speed it was fired at" because the only force acting on it will be gravity, not with the force of the explosives behind it
Uh... you're wrong. Unless you ignore the fact that the people who said that also said in the absence of air resistance - in which case, just your reasoning is wrong. The only force acting on the bullet once it leaves the barrel is gravity. It doesn't matter that the force that accelerated it was created by explosives, it will act the same way as any other object that is propelled upward. If you throw a ball straight up, it will come down at the same speed as when it left your hand, minus air resistance.
even if you were to fire exactly straight up and eliminate wind as a factor, the bullet would still not come straight down since the earth is spinning underneath the bullet.
Yeah I'm pretty sure you're wrong too. The bullet would rotate with the earth. As an anolgy, if you hold a ball out the window of your car and drop it, it will not fall straight down - its initial horizontal velocity will be the same as your car's. Works the same with the bullet - it is rotating at 1000 mph (or less as you move away from the equator) before it leaves the barrel, and will continue to do so after it leaves the barrel. Regardless, it would be very difficult to shoot it dead on straight up.
The speed the bullet is travelling will depend a lot on the trajectory at which it is fired. If it is fired at a low enough trajectory that it does not go very high, but high enough that it still loses all of its horizontal velocity to wind resistance before it falls, then it would likely be moving slower than its terminal velocity when it hits the ground (or some unsuspecting person). But IT WOULD STILL HURT so don't do it.
