What does (5+(10(n-1))^2 equal?

[Howard]

It's been a long time since I've done this.

 

[MailBoxHead]

e=mc

 

[dighn]

well 5 + 10(n-1) is an arithemtic series that goes like 5, 15, 25... and ^2 is the square of that . what do you mean waht is that equal do? i dont understna d your question

 

[Howard]

Yes, I needed to find an equation that would represent integers that end in 5. But I need to square it and I don't know how to do that.

 

[dighn]

Originally posted by: Howard
But I need to square it and I don't know how to do that.

wth do you mean? you mean squares that end with 5?

 

[HonkeyDonk]

(5+(10(n-1))^2 doesn't equal anything because its an expression.

Unless you give a value for n, then will it equal something.

 

[Howard]

I want it expanded (right term)?

like (x + 2)^2 is x^2 + 4x + 4.

 

[Howard]

n * 2 is equal to 2n!

 

[dmw16]

ok

first let's make that equation into:

(5 + 10n -10)^2

now that is the same as:

(10n - 5)^2

and that is trivial to do...

100n^2 - 100n + 25

thats it.
-doug

 

[dighn]

oops nm

 

[jonmullen]

simplified it is 100n^2-100n+25 I think and you can factor out 25 and get 25(5n^2-5n+1) now you can solve if you cant set it equal to something, but you said nothing about that.

 

[Howard]

Originally posted by: dighn
20n^2 - 20n + 5

Thanks

 

[dighn]

Originally posted by: Howard

Originally posted by: dighn
20n^2 - 20n + 5

Thanks

no no that's wrong. multiple every term by 5

 

[Howard]

Originally posted by: dighn

Originally posted by: Howard

Originally posted by: dighn
20n^2 - 20n + 5

Thanks

no no that's wrong. multiple every term by 5

:Q

 

[Kadarin]

Step by step..

(5+(10(n-1))^2
(5+10n-10)^2
(10n-5)^2
(10n-5)(10n-5)
100n2-100n+25

 

[Howard]

Originally posted by: Astaroth33
Step by step..

(5+(10(n-1))^2
(5+10n-10)^2
(10n-5)^2
(10n-5)(10n-5)
100n2-100n+25

That really cleared it up. Thank you!

 

[hdeck]

Originally posted by: Astaroth33
Step by step..

(5+(10(n-1))^2
(5+10n-10)^2
(10n-5)^2
(10n-5)(10n-5)
100n2-100n+25

he's got it

 

[yellowperil]

You guys are smrt

 

[Kyteland]

Um, there's an extra open parenthesis there. I 'll assume that the last one goes on the end, like so: (5+(10(n-1))^2)

(5+(10(n-1))^2)
(5+(10*n-10)^2)
(5+(100*n^2-200*n+100))
(100*n^2-200*n+105)

Depending on where that closing parenthesis goes, you get different answers

 

[jonmullen]

Originally posted by: Astaroth33
Step by step..

(5+(10(n-1))^2
(5+10n-10)^2
(10n-5)^2
(10n-5)(10n-5)
100n2-100n+25

Thats not simplified though, you can still factor 25 out.