Way to launch a program window in XP in a specific location

[ColKurtz]

We have an app that, for known reasons, does not retain its settings upon reboot. Manual reconfiguration on every reboot is not an attractive option, and it is not scriptable. Our interim solution is to use software that records mouse movements, and that "script" will run on every reboot and the mouse will click in the start menu (or a desktop icon or whatever) and then choose the appropriate settings.

My concern is the app opening in a different place than it was when the mouse gestures were recorded. Since the mouse will be moving to specific x/y pixel locations when clicking, if the window opens somewhere else this won't work.

Is there a way to open windows in a specific x/y area of the desktop (preferably without another applet) under XP?

Thanks in advance.

 

[t0mn8r]

ColKurtz,
I have some experience in scripting in a test environment using automatic tools.

We had a similar issue a while back so we scripted a maximise screen function into each script. This means that when a screen is called up the first step was to maximise it. Then, when the cursor is positioned on the screen it is always in the same place.

Screen positioning is dynamic depending on the app.

HTH

 

[MrChad]

Does the app retain its settings upon exiting/reopening (without a reboot)?

 

[ColKurtz]

Thanks. We were able to get it working today. I ran into my concern right away -- a settings window popped up in a different location every time we called it. Luckily, the application shortcut would launch in full-screen mode (some apps do not obey this), and popped up in the same place when maximized.