>>Ffriction = co-efficient * normal force
>>Ffriction = co-efficient * 2/3mg
>>co-efficient = 2Ffriction / 3mg
co-efficient = 3/2 (Ffriction / mg) , no???
Handle: Interesting... but we still perceive at a certain rate correct? (i.e. brain kinetics, translation of frequencies, etc.) There must be some finite number, it can't be just some continuous fluid sequence.
>>Ffriction = co-efficient * 2/3mg
>>co-efficient = 2Ffriction / 3mg
co-efficient = 3/2 (Ffriction / mg) , no???
Handle: Interesting... but we still perceive at a certain rate correct? (i.e. brain kinetics, translation of frequencies, etc.) There must be some finite number, it can't be just some continuous fluid sequence.
