Unsigned Division in Intel 8086 Assembler using only register shifts

[acemcmac]

?

 

[acemcmac]

bump for more info, I just relized some people were actually forced to use 8085 :shocked:

 

[warcrow]

I have no idea wtf you're talking about, but it sounds really disappointing.

 

[TechBoyJK]

is that a group of intel employees moving around the cash registers in the break room?

 

[DNvCross]

I'm the sucker who was forced to do this on an 8085 chip. mult and div weren't even available.

 

[TerryMathews]

If you're asking what I think your asking (Implement division of two integers without using DIV), I had to do this in my ASM class. It was for a 68000 though.

Here's an algorithm for it.

 

[tfinch2]

Originally posted by: TerryMathews
If you're asking what I think your asking (Implement division of two integers without using DIV), I had to do this in my ASM class. It was for a 68000 though.

Here's an algorithm for it.

Although that works he's inquiring about just register shifts. Do your own HW OP.

 

[TerryMathews]

Originally posted by: tfinch2

Originally posted by: TerryMathews
If you're asking what I think your asking (Implement division of two integers without using DIV), I had to do this in my ASM class. It was for a 68000 though.

Here's an algorithm for it.

Although that works he's inquiring about just register shifts. Do your own HW OP.

You're right, I read over that part and just saw the registers bit.

Now I'm intrigued - I can't imagine how you could handle any case using only shifts. Someone post the answer!

 

[tfinch2]

You can divide by powers of two by using the shr instruction.