TitanDiddly
Guest
96%
Originally posted by: Vic
86% but I flew through it in like 5 minutes.
Hmm... reviewing it, it looks like I made a couple of stupid mistakes caused by going too fast (most transposed answers), but I disagree with #48. If air enters the cylinder due to atmospheric pressure pushing it in (rather than suction from the piston going down on the intake stroke) then how do they explain intake manifold vacuum?
Originally posted by: Scouzer
Originally posted by: ayabe
Originally posted by: thirdeye
Ouch I got a 66% 🙁
I sucked at the weighted pulley questions. Got them all wrong.
Me too and I don't know circuits because I never took physics.
The pulley ones with the weights, I had no clue.
Are you kidding? Those circuits were Grade 9 Science for me...
Originally posted by: Zenmervolt
I swear that they have question 11 marked wrong. Unless I'm having trouble reading the rotational direction of the worm gear.
ZV
Originally posted by: Zenmervolt
I swear that they have question 11 marked wrong. Unless I'm having trouble reading the rotational direction of the worm gear.
ZV
Originally posted by: mariok2006
Originally posted by: Zenmervolt
I swear that they have question 11 marked wrong. Unless I'm having trouble reading the rotational direction of the worm gear.
ZV
Yeah, that question is definitely wrong IMO
Originally posted by: Zenmervolt
Originally posted by: mariok2006
Originally posted by: Zenmervolt
I swear that they have question 11 marked wrong. Unless I'm having trouble reading the rotational direction of the worm gear.
ZV
Yeah, that question is definitely wrong IMO
I just played around with a bolt that I have laying on my desk. The question is right, I was wrong. I looked at things completely arse-backwards.
The rotation direction is essentially "un-screwing" the worm gear. This would create a force pushing the worm gear to the right. Since the worm gear is fixed laterally, that force will act on the spur gear (which is free to rotate), causing the spur gear to spin counter-clockwise.
ZV
For the lever question, I was also taught to model distributed masses as points for the sake of the FBD moment calculations. For that problem, it would be a 1:5 distance ratio, not 1:3.Originally posted by: DrPizza
And, (correct me if I'm mistaken), the two masses balanced on a lever resting on a fulcrum. The one on the left is 300kg. The "correct" answer is 100kg. I disagree. It's been 20 years since I've done such problems, but I thought center of mass was used, in which case the one on the right was 5 times as far away, not 3 times as far away. (Darn those profs who spent too much time on "point masses" and not enough on real world masses!"
Originally posted by: DrPizza
And, (correct me if I'm mistaken), the two masses balanced on a lever resting on a fulcrum. The one on the left is 300kg. The "correct" answer is 100kg. I disagree. It's been 20 years since I've done such problems, but I thought center of mass was used, in which case the one on the right was 5 times as far away, not 3 times as far away. (Darn those profs who spent too much time on "point masses" and not enough on real world masses!"