not going to happen. Even 200$ computer speakers distort at "party" volumes.
My definition of "party" volumes is:
1. 10-20 feet away from speakers
2. 95dB avg
3. 10-20 people
I list these 3 things because sound intensity drops similarly to the inverse square law (double the distance relates to an approximate 6dB drop in SPL). 95dB is pretty loud, but is the typical loudness of parties and has it's own requirements of the speaker cones, tweeters, and amplification. I mention the number of people as people act as sound absorbers and further decrease the loudness, thus requiring an increase in the volume.
Additionally, computer speakers are designed to provide for "adequate" loudness and distortion in the near-field (~3-5 feet). Can they do ~95dB in the near field with no people blocking the sound, most likely (at least 100-200$ ones). Can 30$ ones? Most likely not. Can 50-90$ ones? - maybe, but would be straining doing such.
So, by doubling the distance you are (in basic terms) quadrupling the power requirement of the speaker's amplifier. If the speaker's amplifier can supply the power, you still have the tweeter and woofer's requiring the ability to move more sound as dictated by the additional power and to be able to properly dissipate the heat energy without melting the voice coil. There are many other factors, but these specific factors are the major compromise points when price comes into the picture.
What is your definition of "party" volumes?