• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

The Drag Race

deanx0r

Senior member
Someone brought this problem to me the other day which I found rather interesting because it doesn't require extensive maths or physics know-how to be solved. Answer will be posted by friday 15th.

James and Harold are drag racing from a standing start and at a constant acceleration.

James covers the last quarter of the distance in 3 seconds.

Harold covers the last third of the distance in 4 seconds.

Who wins the race, and by how much?

Hint for those without the physics background: start with the following kinematic equation.

d= v0 + (1/2)at^2

where d is the distance, v0 is the initial speed, t is time and a is acceleration.
 
run-baby-run.jpg


Which one is James and which one is Harold?
 
Cars do not accelerate at a set pace. This is not how drag racing works.

Give us their ET's and trap speeds. ;P
 
Someone brought this problem to me the other day which I found rather interesting because it doesn't require extensive maths or physics know-how to be solved. Answer will be posted by friday 15th.

James and Harold are drag racing from a standing start and at a constant acceleration.

James covers the last quarter of the distance in 3 seconds.

Harold covers the last third of the distance in 4 seconds.

Who wins the race, and by how much?

Hint for those without the physics background: start with the following kinematic equation.

d= v0 + (1/2)at^2

where d is the distance, v0 is the initial speed, t is time and a is acceleration.

It really depends how much distance they covered previous to last quarter and third.

Without knowing those #s, it would be impossible to get a resolution.
 
Ok, call me crazy, but if they are both at a standing start (v0=0) and they both are accelerating at the same rate (a) then at any time (t), they will both have covered the same distance (d). So all other information is irrelevant - the race is a tie.
 
Ok, call me crazy, but if they are both at a standing start (v0=0) and they both are accelerating at the same rate (a) then at any time (t), they will both have covered the same distance (d). So all other information is irrelevant - the race is a tie.

Either that or each car accelerates at a different constant rate.
 
Ok, call me crazy, but if they are both at a standing start (v0=0) and they both are accelerating at the same rate (a) then at any time (t), they will both have covered the same distance (d). So all other information is irrelevant - the race is a tie.

The acceleration is constant, but they both accelerate at a different rate.

It really depends how much distance they covered previous to last quarter and third.

Without knowing those #s, it would be impossible to get a resolution.

Hint for those trying to set this up:

You can split up the race in two parts. For James' race, you know he covered the first 3/4 distance with an initial velocity of 0 (v0). And the last 1/4 distance was covered in 3 seconds.


|_________3/4d_______________|____1/4d____|

From d= v0t + (1/2)at^2 you then have
3/4d = 1/2at^2 + v0t

Solving for d , you have:
d = 2/3at^2

Now for the last 1/4 of the race.
He covered the last 1/4 in 3 seconds.

1/4d = 1/2a(3)^2 + v(3)
Velocity can also be expressed as v = at where t is the time at the 3/4 mark.
1/4d = 1/2a(3)^2 + at(3)

Solving for d , you have:
d = 18a+12at

It's almost there, right?
 
by my rough estimate, I think the second dude won.

Even at constant velocity, the 2nd dude covered the last 1/4 in 2.99 second, but he was accelerating so the time it took him to cover the .0825 of the distance was definitely more than the time to cover the last .25 of the distance. so the 2nd dude covered the last .25 of the distance in less than 2.99 seconds... as the acceleration was constant, he definitely was faster in the last .25 of the distance. So my Vote - Dude #2
 
Last edited:
I calculate Harold wins with a run of 21.80 seconds.
James finishes in 22.38 seconds.

Yup, that is the correct answer. Good job.

I am posting the solution below.


gif.latex


gif.latex


the remainder quarter of the race can can be written as followed:

gif.latex


gif.latex


gif.latex


gif.latex


Set them both equal to each other to solve for t:

gif.latex


gif.latex


gif.latex
 
Back
Top