Something for the OT'ers - Candy Mathematics.

thereds

Diamond Member
Apr 4, 2000
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Alright, first of all, no cheating. That is, in this case, no scrolling down before you finish doing what is required of you. It takes less than a minute to complete. Trust me this is kinda cool.
Here we go:

1. First of all, pick the number of times a week that you would like to have candy (try to shoot for more than once but less than 10).














2. Multiply this number by 2.















3. Add 5 to the number that you have right now.















4. Multiply it by 50. [yes, you can use a calculator.]















5. If you have already celbrated your birthday this year add 1750 to the number.
If you haven't, add 1749.















6. Now subtract the four digit year that you were born.





You should now have a three digit number.
The first digit is the original number you picked earlier ie, the number of days you'd like to have candy.
The second and third digits are your current age.

Voila.
By the way, this only works in the year 2000, I think.
 

thereds

Diamond Member
Apr 4, 2000
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Then you probably would start to need the services of a dentist in the near future.
 

Russ

Lifer
Oct 9, 1999
21,093
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<< but less than 10 >>



Sorry, but I'm disqualified from participation.

Russ, NCNE
 

Regine

Diamond Member
Sep 11, 2000
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I just used the &quot;ideal # of times I should have candy&quot;.
Otherwise I would be excluded too :D
 

Pretender

Banned
Mar 14, 2000
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Man, I can't believe they still make problems like this.

Analysis- let n = the number you chose, let z = your year of birth (for this example, assume you're birthdate already occured, but it's not important)

Step 1, result = n
Step 2, result = 2n
Step 3, result = 2n+5
Step 4, result = 100n+250
Step 5, result = 100n+250+1750
Step 6, result = 100n+2000-z



<< You should now have a three digit number.
The first digit is the original number you picked earlier ie, the number of days you'd like to have candy.
The second and third digits are your current age.
>>


The first part, 100n, makes it so that n is always multiplied by 100, so the first digit will always be the number you originally chose (unless your age is also greater then 100, in which case the maker of this puzzle gets put in front of the firing squad.
The second part is just 2000 minus your DOB, which would obviously be your birthdate. Change 1750 to 1751 next year.
 

thereds

Diamond Member
Apr 4, 2000
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dood. aren't you tha

just something I got in my e-mail and I thought I'd share.